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elena-s [515]
4 years ago
12

Consider the model of a sodium atom. An orange circle labeled upper N a is surrounded by three concentric circles. The innermost

ring has dots at the north and south positions. The next ring has eight dots, evenly spaced, with dots aligning with those in the inner ring. The outermost ring has one dot at the north position. Which feature does the model show accurately?
A) the size of the electrons in different shells
B) the shapes of the orbitals in different shells
C)the distribution of electrons in different shells
D)the orientation of the orbitals in different shells
Chemistry
2 answers:
alex41 [277]4 years ago
6 0

Answer:

C would be the answer.

Explanation:

Nuetrik [128]4 years ago
6 0

Answer:

C.

Explanation:

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Nuclear equations<br><br> 1/0n + / = 236/92 U
andre [41]

Answer:

I think this may help

Explanation:

Sum of subscripts on left = 92. Sum of subscripts on right = 57. So X must have atomic number = 92 – 57 = 35. Element 35 is bromine.

7 0
4 years ago
Describe three devices used in radiation detection
xeze [42]
<span>MicroR Meter, with Sodium Iodide Detector
<span>Geiger Counter, with Geiger-Mueller (GM) Tube or Probe
<span>Portable Multichannel Analyzer</span>

</span>

</span>
6 0
3 years ago
Match the following descriptions with the correct polysaccharide, note if you answer any part of this question incorrectly a sig
Ad libitum [116K]

Answer:

Glycogen. Cellulose. Amylose. Cellulose. Amylopetin and Glycogen. Amylopetin and Cellulose.

Explanation:

Glycogen is the form that glucose is stored in human body.

Cellulose is the structural part of plant cell walls and human cannot digest it.

Amylose is the polysaccharide linked mainly by the the bonds of \alpha 1,4 glycosidic.

Cellulose is an unbranched polysaccharide linked mainly by the bonds of  \beta 1,4 glycosidic.

Amylopetin and Glycogen are branched polysaccharides linked by the bonds of \alpha 1,4 glycosidic and \alpha 1,6 glycosidic.

Amylopetin and Cellulose are mainly stored in plants.

4 0
4 years ago
How many moles of ethyl alcohol, C2H6O, are in a 18.0 g sample?
Arte-miy333 [17]
To find moles in this sample, you would divide grams by molar mass of ethyl alcohol
(18.0g)/(46.07g/mol) = 0.391mol C2H6O
4 0
4 years ago
Question 3 (1 point)
Hoochie [10]

Answer:

50 mol

Explanation:

Mass of methane = 800 g

Number of moles of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂      →      CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles = 800 g/ 16 g/mol

Number of moles = 50 mol

Now we will compare the moles of methane and carbon dioxide from balanced chemical equation.

                CH₄        :         CO₂

                   1           :          1

                 50          :        50

4 0
3 years ago
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