A toaster is plugged into a 120-volt household circuit. It draws 5 amps of

1 answer:

6 0

A. Resistance R is a fraction of voltage over current:
$R=\frac{U}{I}=\frac{120V}{5A}=24Ohm$

b. The power of the toaster P is a multiplication of voltage:
$P=U*I=120V*5A=600W$

c. 1 kW = 1000W then:
$P_{kW}=0,6kW$

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