if the radius of the capillary tube is doubled, what changes will take place in the hieght of rise of liquid with capacity tube
1 answer:
Explanation:
The height of the rise of liquid with capillary tube is given by the formula as follows :
Where
r is radius
It is clear that the height of the rise of liquid is inversely proportional to the radius of the capillary tube.
If the radius of the capillary tube is doubled, it means the height of rise of liquid with capillary tube become half.
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Answer:
a
b
Explanation:
From the question we are told that
The initial position of the particle is
The initial velocity of the particle is
The acceleration is
The time duration is
Generally from kinematic equation
=>
=>
Generally from kinematic equation
Here s is the distance covered by the particle, so
=>
Generally the final position of the particle is
=>
=>
Answer:
The current value of the Hubble's constant = 73 km/sec/Mpc.
t = 71.9 trillion years will be the new age of universe if the Hubble constant = 700 km/s/Mpc
Explanation:
The current value of the Hubble's constant = 73 km/sec/Mpc. However, recent discoveries in the cosmology contradicts the idea of Hubble constant as being fixed. Some scientists are not agreeing on this value and the debate is going on.
Hubble law states that how fast universe is expanding or in other words, galaxies are expanding separating with a speed directly proportional to the distance of galaxies to the earth.
Hence,
v is directly proportional to d
where, v = apparent velocity
d = distance
if we equate velocity and distance then there comes Hubble constant.
v = x d
= 73 km/sec/Mpc
where, Mpc = Mega Parsec = 1 Mpc = 3.086 x km
We can use Hubble constant to tell the age of universe.
t = d/v
t = d/( xd)
t = 1/
Scientist calculated the age of universe by using Hubble constant, which is 13.4 billion years.
Now, if we hypothetically change the value of Hubble constant,
from = 73 km/sec/Mpc to
= 700 km/sec/Mpc
then the age of universe will be:
t = 1/
first convert the units of new into 1/s
= (700) x (/3.08 x
)
= 227.27 x
= 2.27 x
1/s
So,
Age of universe will be:
t = 1/ = 1/2.27x
1/s
t = 2.27 x s
t = 71.9 trillion years
t = 71.9 trillion years will be the new age of universe if the Hubble constant = 700 km/s/Mpc