Question

Which are the roots of the quadratic function f(b) = b2 – 75? Check all that apply.

Answer 1

$f(b)=b^2-75 \\f(b)=0 \\b^2-75=0 \\b^2=75 \\b=\pm\sqrt{75}=\pm\sqrt{25\times3}=\pm5\sqrt{3}$

Answer 2

Answer:

The roots of the given quadratic function $f(b) = b^2-75$ is $5\sqrt{3}\quad$ and $-5\sqrt{3}\quad$  

Step-by-step explanation:

   Given: Quadratic function $f(b) = b^2-75$

We have to find the roots of the given quadratic function $f(b) = b^2-75$

Since, roots of the quadratic equation is the points where the value of function is zero.

That is f(x) = 0

Consider the given function  $f(b) = b^2-75$

Put f(b) = 0

$\Rightarrow b^2-75=0$

Simplify , we have,

$\Rightarrow b^2=75$

Taking square root both side, we have,

$\Rightarrow b=\sqrt{75}$

Simplify we have,

$\Rightarrow b=\pm 5\sqrt{3}\quad$

Thus, The roots of the given quadratic function $f(b) = b^2-75$ is $5\sqrt{3}\quad$ and $-5\sqrt{3}\quad$