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Olenka [21]
3 years ago
8

What is the percentage of sodium presents in sodium hydrogen carbonate NaHCO3

Chemistry
1 answer:
STatiana [176]3 years ago
3 0

Answer:-

27.38%

Explanation:-

Molecular weight of sodium hydrogen carbonate NaHCO3

= 23 x 1 + 1 x 1 + 12 x 1 + 16 x 3

= 84 gram

Total sodium Na present in NaHCO3 = 23 x 1 = 23 gram

Percentage of sodium present=

Total sodium x 100/ (Total molecular weight)

= 23 x 100 / 84

= 27.38 %

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Answer:

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Explanation:

We'll begin by calculating the volume of the diluted solution. This can be obtained as follow:

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