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3 years ago

Write uses of Co-60 .

Chemistry

2 answers:

Makovka662 [10]3 years ago

5 0

Answer:

Co-60 is used medically for radiation therapy as implants and as an external source of radiation exposure. It is used industrially in leveling gauges and to x-ray welding seams and other structural elements to detect flaws. Co-60 also is used for food irradiation, a sterilization process.

Explanation:

ivolga24 [154]3 years ago

4 0

Answer:

Cobalt Sources

Cobalt-60 is used as a radiation source in many common industrial applications, such as in leveling devices and thickness gauges. It is also used for radiation therapy in hospitals. Accidental exposures may occur as the result of loss or improper disposal of medical and industrial radiation sources.

Explanation:

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What is the correct electron configuration of the element with atomic number 20?

IgorLugansk [536]

Answer:

D is the correct answer

s orbital contain 2

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3 years ago

Given the equation representing a reversible reaction:

tester [92]

Answer:

- Acetic acid (CH₃COOH) and hydronium ion (H₃O⁺)

Explanation:

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In this case, based on the acid-base theory which states that acids are known as H⁺ donors, if we consider the direct reaction:

$CH_3COOH(aq) + H_2O \rightarrow CH_3COO^-(aq) + H_3O^+(aq)$

It is clear that the acetic acid is the first H⁺ donor as it losses one H⁺ to turn into the acetate ion. Moreover, if we consider the inverse reaction:

$CH_3COO^-(aq) + H_3O^+(aq)\rightarrow CH_3COOH(aq) + H_2O$

It is also clear that the hydronium ion is the second H⁺ donor as it losses one H⁺ to turn into water.

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3 years ago

"A crosslinked copolymer consists of 57 wt% ethylene (C2H4) repeat units and 43 wt% propylene (C3H6) repeat units. Determine the

ch4aika [34]

Explanation:

Percentage ethylene by weight = 57%

Percentage propylene by weight = 43%

Suppose in 100 grams of polymer:

Mass of ethylene = 57 g

Mass of propylene = 43 g

Moles of ethylene = $\frac{57 g}{28 g/mol}=2.036 mol$

Moles of propylene = $\frac{43g}{42g/mol}=1.024 mol$

1 mole = $N_A =6.022\times 10^{23}$ molecules/ atoms

Units of ethylene = $2.036 mol\times N_A$

Units of propylene = $1.024 mol\times N_A$

a) Fraction of ethylene units:

$=\frac{2.036 mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{509}{765}$

b ) Fraction of propylene units:

$=\frac{1.024mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{256}{765}$

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3 years ago

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d. nonrenewable resource

Explanation:

A nonrenewable source is a source of economic value that cannot be immediately displaced by natural means on a level equal to its destruction. Most fossil fuels, such as oil, natural gas, and coal are estimated nonrenewable resources in that their use is not sustainable because their production takes billions of years.

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4 years ago

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Write uses of Co-60 .​

Write uses of Co-60 .