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steposvetlana [31]
4 years ago
5

a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre

d to a container with a volume of 18.5L
Chemistry
1 answer:
zhannawk [14.2K]4 years ago
3 0
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr

The final pressure exerted by the gas would be 0.593 torr.

Hope this helps!
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324.554 K

Explanation:

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Once again thus answer can be found using the gas law P1/T1 =P2/T2

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If 15.0 g of nitrogen reacts with 15.0 g of hydrogen, 10.5 g of ammonia is
Alexxx [7]

Answer:

Percent yield =  57%

Explanation:

Given data:

Mass of nitrogen = 15.0 g

Mass of hydrogen = 15.0 g

Mass of ammonia produced = 10.5 g

Percent yield = ?

Solution:

Chemical equation:

N₂+ 3H₂      →   2NH₃

Number of moles of hydrogen:

Number of moles = mass/molar mass

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Number of moles = 7.5 mol

Number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 15.0 g/ 28 g/mol

Number of moles = 0.54 mol

Now we will compare the moles of ammonia with nitrogen and hydrogen from balance chemical equation.

              N₂       :        NH₃

               1         :          2

           0.54       :     2×0.54 = 1.08

             H₂         :           NH₃

              3           :            2

              7.5        :      2/3×7.5= 5 mol

Theoretical yield of ammonia:

Mass = number of moles × molar mass

Mass = 1.08 × 17 g/mol

Mass = 18.36 g

Percent yield:

Percent yield = (actual yield / theoretical yield) ×100

Percent yield = (10.5 g/ 18.36 g) ×100

Percent yield = 0.57 ×100

Percent yield =  57%

8 0
3 years ago
Fill in the blank
soldi70 [24.7K]
Northern hemisphere
5 0
4 years ago
How many moles are in 3.4×10^23 molecules of H2SO4
Kazeer [188]
1 mole ----------- 6.02x10²³ molecules
? moles ---------- 3.4x10²³ molecules

(3.4x10²³) x 1 / 6.02x10²³ =

3.4x10²³ / 6.02x10²³ => 0.564 moles of H2SO4
6 0
3 years ago
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