All categories

3 years ago

What is the ratio of drivers to cars in a stock car race?

Mathematics

1 answer:

adoni [48]3 years ago

5 0

It would be a 1-1 ration because there is 1 driver for every stock car

You might be interested in

What is the answer to this 4×3^2?<br><br>Evaluate the expression.

Neporo4naja [7]

The answer to this question is 36

6 0

3 years ago

Read 2 more answers

The cost of 9 scares is $78.75 what is the unit price ?

Vlad [161]

Answer:

$8.75

Step-by-step explanation:

5 0

2 years ago

Plz solve it is ergent <br>

soldier1979 [14.2K]

Answer:

first term = 2 ...(given)

second term = f (2) = f (2-1) * 5 = 1 * 5 = 5. .....[according to the formula f(n) = f (n -1) *5 ]

third term = f (3) = f ( 3 - 1 ) * 5 = 2 * 5 = 10

fourth term = f (4) = f (4 - 1) * 5 = 3 * 5.= 15

fivth term = f (5) = f ( 5 - 1) * 5 = 4* 5. =20

7 0

3 years ago

3 more than 6 times a number

Snowcat [4.5K]

Answer:

assuming you're looking for an expression, it would be written as "6x+3".

4 0

3 years ago

Read 2 more answers

In a chess variant, a "lord" can move one space at a time, either upward, or to the right, or diagonally up and to the right. ho

valentina_108 [34]

There are 48639 ways for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard

<h3>Further explanation</h3>

The probability of an event is defined as the possibility of an event occurring against sample space.

$\large { \boxed {P(A) = \frac{\text{Number of Favorable Outcomes to A}}{\text {Total Number of Outcomes}} } }$

<h2>Permutation ( Arrangement )</h2>

Permutation is the number of ways to arrange objects.

$\large {\boxed {^nP_r = \frac{n!}{(n - r)!} } }$

<h2>Combination ( Selection )</h2>

Combination is the number of ways to select objects.

$\large {\boxed {^nC_r = \frac{n!}{r! (n - r)!} } }$

Let us tackle the problem.

This problem is similar to Pascal Triangle.

The Lord can move to the right or up in one way only.

We can put "1" in each box on the bottom and left to represent 1 possible movement.

To get the possibility of movement to another box, we will add the possibility of movement to the left, right, and diagonal squares as shown in Figure 1.

This process is repeated for the next box as shown in Figure 2.

Finally, after this process is repeated until the top right box, we get the results as shown in Figure 3.

There are 48639 ways for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard.

<h3>Learn more</h3>

Different Birthdays : brainly.com/question/7567074
Dependent or Independent Events : brainly.com/question/12029535
Mutually exclusive : brainly.com/question/3464581

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Probability

Keywords: Probability , Sample , Space , Six , Dice , Die , Binomial , Distribution , Mean , Variance , Standard Deviation

7 0

3 years ago