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Dafna1 [17]
3 years ago
8

A bullet of mass 12 g strikes a ballistic pendulum of mass 2.2 kg. The center of mass of the pendulum rises a vertical distance

of 10 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.
Physics
1 answer:
Mrrafil [7]3 years ago
8 0

Answer:

The  bullet's initial speed 258.06 m/s.

Explanation:

It is given that,

It is given that,

Mass of the bullet, m₁ = 12 g = 0.012 kg

Mass of the pendulum, m₂ = 2.2 kg

The center of mass of the pendulum rises a vertical distance i.e. h = 10 cm = 0.1 m

We need to find the initial speed of the bullet. Here, the kinetic energy of the bullet gets converted to potential energy of the system as :

\dfrac{1}{2}(m_1+m_2)V^2=(m_1+m_2)gh

V=\sqrt{2gh}....................(1)

Where

V is the speed of bullet and pendulum at the time of collision.

Let v be the initial speed of the bullet. Using conservation of momentum as :

m_1v=(m_1+m_2)V

V=(\dfrac{m_1+m_2}{m_1})\sqrt{2gh}

V=(\dfrac{0.012\ kg+2.2\ kg}{0.012 kg})\sqrt{2\times 9.8\ m.s^2\times 0.1\ m}

V = 258.06 m/s

So, the initial speed of the bullet is 258.06 m/s. Hence, this is the required solution.

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Which is the electric potential energy of a charged particle divided by its charge?Electric fieldelectric field lineelectric pot
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<h3><u>Answer;</u></h3>

electric potential

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Mathematically; V =PE/q

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Two cars collide at an intersection. One car has a mass of 1600 kg and is
pickupchik [31]

The combined momentum is 4000 kg m/s south

Explanation:

The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.

For this problem, we choose north as positive direction and south as negative direction.

The momentum of the first car travelling north is given by:

p_1 = m_1 v_1

where

m_1 = 1600 kg is the mass of the car

v_1 = +8 m/s is its velocity

Substituting,

p_1 = (1600)(8)=+12800 kg m/s

The momentum of the second car travelling south is given by:

p_2 = m_2 v_2

where

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Substituting,

p_2 = (1400)(-12)=-16800 kg m/s

And therefore, the combined momentum is

p=p_1 + p_2 = +12800 + (-16800)=-4000 kg m/s

where the negative sign means the direction of the total momentum is south.

Learn more about momentum:

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