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nevsk [136]
3 years ago
14

10. Hamilton How long does it take Lewis travelling at 156 m.p.h to cover 16 miles?

Physics
2 answers:
Anvisha [2.4K]3 years ago
6 0

Answer: Hello!

Lewis is travelling at 165 mph, which means miles per hour, this says that he does 165 miles in one hour.

We want to know how much time takes to cover 16 miles.

this can be calculated as the quotient of the distance and the velocity; this is:

t = \frac{16 mi}{165 mi/h} = 0.096 h

if we want to write this in minutes, then:

we know that one hour has 60 minutes, then 0.096 hours has:

0.096h*60mins/1h = 5.8 minutes.

then Lewis needs 5.8 minutes in order to cover 16 miles if his speed is 156 miles per hour.

MAVERICK [17]3 years ago
6 0
\frac{16m}{156m/h}  = .1h
.1h * 60min/h = 6 minutes.
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tankabanditka [31]

Answer:

Work done, W = −287500 Joules

Explanation:

It is given that,

Mass of the car, m = 920 kg

The car is travelling at a speed of, u = 90 km/h = 25 m/s

We need to find the amount of work must be done to stop this car. The final velocity of the car, v = 0

Work done is also defined as the change in kinetic energy of an object i.e.

W=\Delta K

W=\dfrac{1}{2}m(v^2-u^2)

W=\dfrac{1}{2}\times 920\ kg(0-(25\ m/s)^2)

W = −287500 Joules

Negative sign shows the work done is done is opposite direction.

3 0
3 years ago
A ball is dropped from a window and takes two seconds to reach the ground .it starts from rest and reaches a final speed of 20m/
Akimi4 [234]
The ball can't reach the speed of 20 m/s in two seconds, unless you THROW it down from the window with a little bit of initial speed. If you just drop it, then the highest speed it can have after two seconds is 19.6 m/s .

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3 0
3 years ago
travels along a perfectly flat (no banking) circular track of radius 532 m. The car increases its speed at uniform rate of at ≡
sladkih [1.3K]

Answer:

<em>The coefficient of static friction = 0.392</em>

Explanation:

When the tire starts to skirt, The net force on the car is equal to the maximum friction.

F = μR................ Equation 1

R = mg.............. Equation 2

F = ma ............ Equation 3

Substituting equation 2 and 3 into Equation 1

ma = μmg.

a = μg

μ = a/g................................... Equation 4

Where F = frictional Force, μ = Coefficient of frictional force, R = normal reaction. a = total acceleration of the car. g = acceleration due to gravity.

<em>Note: The tangential acceleration  is perpendicular to the radius. The total acceleration is</em>

a = √(a₁² + a₂²)........................ Equation 4

Where a₁ = tangential acceleration of the tire, a₂ = centripetal acceleration of the car.

a₁ = 2.96 m/s²

a₂ = v²/R..................... Equation 5

Where v = speed of the car = 36.1 m/s, R = radius of the circular part traveled by the car = 532 m

Substituting into equation 5

a₂ = 36.1²/532

a₂ = 1303.21/532

a₂ = 2.45 m/s².

Therefore,

a = √(2.45²+2.96²)

a = √(6.0025 + 8.7612)

a = √14.764

a = 3.84 m/s².

Substituting into equation 4

μ = 3.84/9.8

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<em>Thus the coefficient of static friction = 0.392</em>

<em></em>

5 0
3 years ago
2. A carpenter tosses a shingle off a 9.4 m high roof, giving it an initial horizontal
Aleksandr [31]

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The object's height <em>y</em> at time <em>t</em> is

<em>y</em> = 9.4 m - 1/2 <em>gt</em>²

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<em>v</em> = -<em>gt</em>

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<em>t</em>² = 2 * (9.4 m) / (9.80 m/s²)

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(b) See part (a); it takes the object about 1.9 s to reach the ground.

(c) The object travels a horizontal distance of

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8 0
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vfiekz [6]
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3 0
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