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lyudmila [28]
4 years ago
10

Which action results from the combination of gravity and inertia working on the moon

Physics
2 answers:
alina1380 [7]4 years ago
6 0

The moon's orbit around Earth

barxatty [35]4 years ago
3 0

Answer:

Revolution of moon around the earth

Explanation:

The revolution of moon around the earth.

The gravitational force acting on the moon is balanced by the centripetal force acting on the moon.

Gravitational force of earth on moon is given by

F = G \frac{M m}{r^{2}}

where, M be the mass of earth, m be the mass of moon and r be the distance between moon and earth.

The centripetal force acting on moon is

F = \frac{m v^{2}}{r}

These two forces balance each other and then the moon revolves around the earth in fixed orbit.

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I’m the absence of friction,gravity and all other external forces what kind of speed will an object display if it travels from t
Natali [406]
Velocity Im pretty sure
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3 years ago
The voltage applied across a given parallel-plate capacitor is doubled. How is the energy stored in the capacitor affected?
ikadub [295]

Answer:

The energy stored in the capacitor quadruples its original value.

Explanation:

The energy stored in a capacitor is given by the equation

U=\frac{1}{2}CV^2

where

C is the capacitance

V is the voltage across the plates

The capacitance, C, depends only on the properties of the capacitor, so it does not change when the voltage applied is changed.

Instead, in this problem the voltage applied is doubled:

V' = 2V

So the new energy stored is

U'=\frac{1}{2}C(2V)^2=4(\frac{1}{2}CV^2)=4U

so, the energy stored has quadrupled.

8 0
3 years ago
Astronomers discover an exoplanet, a planet obriting a star other than the Sun, that has an orbital period of 3.27 Earth years i
Naddik [55]

Answer:

  r = 3.787 10¹¹ m

Explanation:

We can solve this exercise using Newton's second law, where force is the force of universal attraction and centripetal acceleration

    F = ma

    G m M / r² = m a

The centripetal acceleration is given by

    a = v² / r

For the case of an orbit the speed circulates (velocity module is constant), let's use the relationship

    v = d / t

The distance traveled Esla orbits, in a circle the distance is

    d = 2 π r

Time in time to complete the orbit, called period

     v = 2π r / T

Let's replace

    G m M / r² = m a

    G M / r² = (2π r / T)² / r

    G M / r² = 4π² r / T²

    G M T² = 4π² r3

     r = ∛ (G M T² / 4π²)

Let's reduce the magnitudes to the SI system

     T = 3.27 and (365 d / 1 y) (24 h / 1 day) (3600s / 1h)

     T = 1.03 10⁸ s

Let's calculate

      r = ∛[6.67 10⁻¹¹ 3.03 10³⁰ (1.03 10⁸) 2) / 4π²2]

      r = ∛ (21.44 10³⁵ / 39.478)

      r = ∛(0.0543087 10 36)

      r = 0.3787 10¹² m

      r = 3.787 10¹¹ m

7 0
3 years ago
A teacher pushed a 98 newton desk across a floor for a distance of 5 meter he exerted a horizontal force of 20 newton for four s
Rom4ik [11]
Missing question: "how much work is done by the teacher?" (found on internet)

Solution:
The work done to move the desk across the floor is equal to
W=Fd
where F is the horizontal force applied to move the desk, and d is the distance covered by the desk. If we use F=20 N and d=5 m, we find the work done:
W=Fd=(20 N)(5 m)=100 J
3 0
3 years ago
Write the type of energy present in pond water and kerosene?​
vichka [17]
Potential and kinetic energy
3 0
3 years ago
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