Ca ionises into Ca^2+. Ca^2+ will be attracted to O^2- ions in the water, since opposite charges attract. (Hydrogen in water forms H^+)
Answer:
2.82 L
T₁ = 303 K
T₂ = 263 K
The final volume is smaller.
Explanation:
Step 1: Given data
- Initial temperature (T₁): 30 °C
- Initial volume (V₁): 3.25 L
- Final temperature (T₂): -10 °C
Step 2: Convert the temperatures to Kelvin
We will use the following expression.
K = °C + 273.15
T₁: K = 30°C + 273.15 = 303 K
T₂: K = -10°C + 273.15 = 263 K
Step 3: Calculate the final volume of the balloon
Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.
V₁/T₁ = V₂/T₂
V₂ = V₁ × T₂/T₁
V₂ = 3.25 L × 263 K/303 K = 2.82 L
Answer:
464.1 J absorbed.
Explanation:
Given data:
Specific heat of zinc = 0.39 J/g°C
Mass of zinc = 34 g
Temperature changes = 22°C to 57°C
Energy absorbed or released = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 57°C - 22°C
ΔT = 35°C
Q = m.c. ΔT
Q = 34 g. 0.39 J/g°C. 35°C
Q = 464.1 J
Explanation:
A chemical reaction is defined as the reaction in which bonds between the reactants either break or form which leads to the formation of a new substance.
For example, 
So, when we drop a sodium metal into water then it produces a frizzing sound which shows the metal is reacting with water.
We know that when two aqueous solutions chemically react with each other then it may lead to the formation of an insoluble substance which is known as precipitate.
This means that formation of a precipitate is also a chemical reaction.
Thus, we can conclude that following are the statements which show evidence for a chemical reaction.
- Dropping sodium metal into water produces fizzing.
- Mixing two aqueous solutions produces a precipitate.
Answer:
The mass of the water in the container is 139.187g
Explanation:
During this process there will not be lost heat. But heat lost of silver is equal to heat won of water
q(lost, silver) = q(gained, water)
-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)
⇒mass of silver = 63.3g
⇒Cpsilver = 0.24J/g °C
⇒initial temperature silver = 384.4 K
⇒ final temperature silver = 292.4 K
⇒mass of water = TO BE DETERMINED
⇒Cpwater = 4.184 J/g °C
⇒initial temperature water = 290.0 K
⇒final temperature = 292.4 K
-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)
-63.3 * 0.24 * (292.4-384.4) = mass * 4.184 * (292.4 - 290.0)
-1397.664 = mass * 0.24 *2.4
mass water = 139.187g
The mass of the water in the container is 139.187g
