According to the ideal gas law, V1/T1=V2/T2. Temperature in the unit of K. So volume is 17*343/161=36.2 mL. The answer is the sample has volume of 36.2 mL.
The correct answer would be letter choice D) Modified mercalli scale, or the fourth option.
Answer: it could be don’t know
Explanation:
Sorry it’s 51
Explanation:
(a) The given data is as follows.
Temperature (T) = = (25 + 273) K = 298 K
= 43000 J/mol
Since, both the liquid and vapors are at equilibrium. Therefore, change in free energy will be calculated as follows.
= 0
43000 - = 0
= -144 J/mol K
Negative sign indicates an increase in entropy of the system.
Now, for 1 mole of is as follows.
= 144 J/K
So, - 214 = 144 J/k
= 358 J/K
Therefore, we can conclude that entropy of vapor is 358 J/K.
(b) As we know that intensive variable are the variables which do not depend on the amount of a substance.
So, in the given situation only temperature will act as an intensive variable that will be required to completely specify the vapor-liquid mixture of .
Answer:
101.98 L
Explanation:
Ideal Gas Law PV = n R T R = gas constant = .082057 L-atm/mol-K
6.35 (V) = 4 * .082057 * 1973
V = 101.98 L