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Studentka2010 [4]
2 years ago
12

How could you increase the sliding friction between the sled and track? How could you decrease it?​

Physics
2 answers:
Oksanka [162]2 years ago
7 0

Explanation:

<h2>If the normal force is the weight of objects you are sliding across the floor, adding or subtracting weight will increase or decrease the sliding friction. But also, if you are pulling an object with a rope, pulling at an upward angle will reduce the normal force.</h2>
Rudik [331]2 years ago
6 0

Answer:

You could put sheet metal lining the bottom or something similar to that

Explanation:

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Dolphins emit clicks of sound for communication and echolocation. A marine biologist is monitoring a dolphin swimming in seawate
LenKa [72]

Answer:

12.64968 Hz

Explanation:

v = Velocity of sound in seawater = 1522 m/s

u = Velocity of dolphin = 7.2 m/s

f' = Actual frequency = 2674 Hz

From Doppler effect we get the relation

f=f'\frac{v-u}{v}\\\Rightarrow f=2674\frac{1522-7.2}{1522}\\\Rightarrow f=2661.35032\ Hz

The frequency that will be received is 2661.35032 Hz

The difference in the frequency will be

2674-2661.35032=12.64968\ Hz

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3 years ago
If a small-diameter open glass tube is partially immersed in a vessel containing mercury, the surface of the mercury inside the
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The pressure outside (atmosphere) is greater than that inside the tube. This means that the mercury will be pushed up in the glass tube. This phenomenon is called the capillary rise. It shape would be like that of the outside of the umbrella. The answer is therefore letter D. 
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3 years ago
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A mass of 0.34 kg is fixed to the end of a 1.4 m long string that is fixed at the other end. Initially at rest, he mass is made
frozen [14]

At time t seconds, the mass has angular speed

\omega = \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t

and hence linear speed

v = (1.4\,\mathrm m) \omega = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t

After 8 s, its linear speed is

v = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) (8\,\mathrm s) = 37.072 \dfrac{\rm m}{\rm s} \approx 37 \dfrac{\rm m}{\rm s}

and has centripetal acceleration with magnitude

a = \dfrac{v^2}{1.4\,\rm m} \approx 981.667\dfrac{\rm m}{\mathrm s^2} \approx 980 \dfrac{\rm m}{\mathrm s^2}

To maintain this linear speed, by Newton's second law the required centripetal force should have magnitude

F = (0.34\,\mathrm{kg}) a \approx 333.767\,\mathrm N \approx \boxed{330 \,\mathrm N}

5 0
2 years ago
An atom has 25 protons 30 neutrons and 25 electrons what is the charge of the atom nucleus
Alex17521 [72]
The nucleus is always positive since thats where the protons are located and the neutrons have no charge....
3 0
3 years ago
A 500g cart moving at 0.25 m/s collides and sticks to a stationary 750g cart. How fast do the two carts
Tresset [83]

Answer:

0.1 m/s

Explanation:

Please see attached photo for explanation.

Mass of 1st cart (m₁) = 500 g

Initial velocity of 1st cart (u₁) = 0.25 m/s

Mass of 2nd cart (m₂) = 750 g

Initial velocity of 2nd cart (u₂) = 0 m/s

Velocity (v) after collision =.?

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(500 × 0.25) + (750 × 0) = v(500 + 750)

125 + 0 = v(1250)

125 = 1250v

Divide both side by 1250

v = 125 / 1250

v = 0.1 m/s

Thus, the two cart will move with a velocity of 0.1 m/s after collision.

3 0
3 years ago
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