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2 years ago

How could you increase the sliding friction between the sled and track? How could you decrease it?

Physics

2 answers:

Oksanka [162]2 years ago

7 0

Explanation:

<h2>If the normal force is the weight of objects you are sliding across the floor, adding or subtracting weight will increase or decrease the sliding friction. But also, if you are pulling an object with a rope, pulling at an upward angle will reduce the normal force.</h2>

Rudik [331]2 years ago

6 0

Answer:

You could put sheet metal lining the bottom or something similar to that

Explanation:

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A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the center

Bess [88]

Answer:

10.93 rad/s

Explanation:

If we treat the student as a point mass, her moment of inertia at the rim is

$I_r = mr^2 = 67.8*3.7^2 = 928.182 kgm^2$

So the system moment of inertia when she's at the rim is:

$I_1 = I_d + I_r = 274 + 928.182 = 1202.182 kgm^2$

Similarly, we can calculate the system moment of inertia when she's at 0.456 m from the center

$I_2 = I_d + 67.8*0.456^2 = 274 + 14.1 = 288.1 kgm^2$

We can apply the law of angular momentum conservation to calculate the post angular speed when she's 0.456m from the center:

$I_1\omega_1 = I_2\omega_2$

$\omega_2 = \omega_1\frac{I_1}{I_2} = 2.62*\frac{1202.182}{288.1} = 10.93 rad/s$

8 0

3 years ago

Una manguera de agua de 1.3 cm de diametro es utilizada para llenar una cubeta de 24 Litros. Si la cubeta se llena en 48 s. A) ¿

Viefleur [7K]

Answer:

We must translate this:

a 1.3 cm diameter water hose is used to fill a 24-liter bucket. If the bucket is filled in 48 s.

A) What is the speed with which the water leaves the hose?

B) if the diameter of the hose is reduced to 0.63 cm and assuming the same flow, what will be the speed of the water leaving the hose?

A) If the velocity of the water is Xcm/s

and the radius of the hose is equal to half its diameter, so it is 1.3cm/2

Then in one second we can considerate that a cylinder of:

V = pi*(1.3cm/2)^2*X cm^3 of water.

So we have that quantity in one second of flow.

where pi = 3.14

then in 48 seconds, the amount of water in the bucket is:

V = 48*pi*(1.3/2)^2*X = 24 L = 24,000 cm^3

Now we need to solve this for X.

48*3.14*(1.3/2)^2*X = 24000

63.679*x = 24000

x = 24000/63.679 = 376.89

So the velocity of the water is 376 cm per second.

B) if the diameter is 0.64cm, we have the equation:

48*3.14*(0.63/2)^2*x = 24000

14.955*X = 24000

X = 24000/14.955 = 1604.814 cm/s

6 0

3 years ago

Select all of the answers that apply. Jenna dives 20meters into the ocean. How much pressure does she feel?

Triss [41]

Use the formula dgh + p atm

d is density g is gravitational field strength h heigh or depth and p atm is atmospheric pressure

1000 x 10 x 20 + 100000 = 300000

almost 300,000 pascal

4 0

3 years ago

That 1.5 kg brick falls to the ground. What is the kinetic energy when the brick is moving at 26 m/s? Formula: Variables: Work w

Tresset [83]

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

$k = \frac{1}{2} m {v}^{2} \\$

m is the mass

v is the velocity

From the question we have

$k = \frac{1}{2} \times 1.5 \times {26}^{2} \\ = \frac{1}{2} \times 1.5 \times 676 \\ = 1.5 \times 338 \\ = 507$

We have the final answer as

Hope this helps you

5 0

3 years ago

Misha Larkins [42]

<span>Cells with similar preferences are arranged closer together in the auditory cortex. </span>That statement presented is True. Auditory cortex is in the temporal lobe. It processes auditory information in human and as well as other invertebrates. The neurons inside the auditory cortex are organized depends on the frequency of the sound.

4 0

3 years ago

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How could you increase the sliding friction between the sled and track? How could you decrease it?​

How could you increase the sliding friction between the sled and track? How could you decrease it?