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Phantasy [73]
2 years ago
15

The equation below can be used to calculate a change in gravitational potential energy. What units must be used for h? Give the

full name, not the abbreviation.
e=m x g x h
Physics
1 answer:
Anni [7]2 years ago
8 0

Answer:

h = change in vertical position (height)

has units of distance.

Explanation:

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Two identical loudspeakers are some distance apart. A person stands 5.20 m from one speaker and 4.10 m from the other. What is t
Igoryamba

Answer:

125.09 Hz

Explanation:

Given : A person stands 5.20 from one speaker and 4.10 m away from the other speaker.

Distance between the speakers is 5.20 - 4.10 =1.10 m

We know that

For destructive interferences

        n . λ / 2

where n =1,3,5,7....

Therefore difference between the speakers is

5.10 - 4.20 = 1 X 0.5 λ

λ = 2.2

Given velocity of sound is V = 344 m/s

Therefore frequency, f = \frac{v}{\lambda }

                                      = \frac{344}{2.2 }

                                      = 156.36 Hz

Now, the third lowest frequency is given by

              λ = (5.20-4.10) X 5 X 0.5

                 = 2.75 m

Therefore frequency, f = \frac{v}{\lambda}

                                      = \frac{344}{2.75}

                                      = 125.09 Hz

Therefore third lowest frequency is 125.09 Hz

5 0
3 years ago
11 1 point
coldgirl [10]

Answer:OPEW

Explanation:

I hope this helps

7 0
2 years ago
In Ørsted’s observation, the current-carrying wire acted like a
hichkok12 [17]
B, C. Also literally a quick search yielded these results, roughly half the time to type this out. 
6 0
3 years ago
Read 2 more answers
In the video "Shoot with great form" Klay says you should rest the ball on
goldfiish [28.3K]
Palm of your hand should be the correct answer if i remember correctly
3 0
2 years ago
What linear speed must an earth satellite have to be in a circular orbit at an altitude of 159 km?
IgorLugansk [536]
Gravitational acceleration, g = GM/r^2. Additionally, for a satellite in a circular orbit, g = v^2/r

Where, G = Gravitational constant, M = Mass of earth, r = distance from the center of the earth to the satellite, v = linear speed of the satellite.

Equating the two expressions;
v^2/r = GM/r^2
v = Sqrt (GM/r);
But GM = Constant = 398600.5 km^3/sec^2
r = Altitude+Radius of the earth = 159+6371 = 6530 km

Substituting;
v = Sqrt (398600.5/6530) = 7.81 km/sec = 781 m/s
8 0
3 years ago
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