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luda_lava [24]
3 years ago
14

Which of these is an example of Newton’s first law of motion?

Physics
1 answer:
alekssr [168]3 years ago
8 0

Answer:

all of them

Explanation:

jk so its D :)

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Naturally occurring element x exists in three isotopic forms: x-28 (27.977 amu, 92.23% abundance), x-29 (28.976 amu, 4.67% abund
Bond [772]

To solve for the weighted average atomic weight of X, all we have to do is to calculate for the contribution of each isotope. The contribution of each isotope on the atomic weight of x is calculated by multiplying their respective atomic weights with the abundance, therefore:

X – 28 = 27.977 amu * (92.23 / 100)

X – 28 = 25.803 amu

 

X – 29 = 28.976 amu * (4.67 / 100)

X – 29 = 1.353 amu

 

X – 30 = 29.974 amu * (3.10 / 100)

X – 30 = 0.929 amu

 

Hence:

X = X – 28 + X – 29 + X – 30

X = 25.803 amu + 1.353 amu + 0.929 amu

<span>X = 28.085 amu</span>

6 0
3 years ago
What is the potential difference across lamp 1
Alex73 [517]

Answer:

1+1=2

Explanation:

You just need to add and voila the answer

7 0
2 years ago
A piston above liquid in a closed container has an area of 1m2. The piston carries a load of 350 kg. What will be the external p
grandymaker [24]
<span>Pressure = force / area</span>

I assume that 350kg is the mass 
Therefore, 

350 x 9.8 (gravity) = 3430N

3430 / 1 = 3430Pa

3.43 KPa


5 0
3 years ago
Read 2 more answers
A 9.0 kg bowling ball races down the lane at 15 m/s before striking a bowling pin (at rest) with a mass of 0.85 kg. If the 0.85
artcher [175]

Answer:

v = 10.75\,\frac{m}{s}

Explanation:

The system ball-pin is modelled by the Principle of Moment Conservation:

(9\,kg)\cdot (15\,\frac{m}{s} ) + (0.85\,kg)\cdot (0\frac{m}{s} ) = (9\,kg)\cdot v + (0.85\,kg)\cdot (45\,\frac{m}{s} )

The velocity of the bowling ball after the collision is:

v = 10.75\,\frac{m}{s}

8 0
3 years ago
Read 2 more answers
When dribbling you should?
Hoochie [10]
D all of the above (:
6 0
3 years ago
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