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DanielleElmas [232]
3 years ago
13

How many additional valence electrons does fluorine need to have a full

Physics
1 answer:
KatRina [158]3 years ago
7 0

Answer:

D= Seven

Explanation:

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A device called an insolation meter is used to measure the intensity of sunlight. It has an area of 100 cm2 and registers 6.50 W
labwork [276]

Answer:

<h2>650W/m²</h2>

Explanation:

Intensity of the sunlight is expressed as I  = Power/cross sectional area. It is measured in W/m²

Given parameters

Power rating = 6.50Watts

Cross sectional area = 100cm²

Before we calculate the intensity, we need to convert the area to m² first.

100cm² = 10cm * 10cm

SInce 100cm = 1m

10cm = (10/100)m

10cm = 0.1m

100cm² = 0.1m * 0.1m = 0.01m²

Area (in m²) = 0.01m²

Required

Intensity of the sunlight I

I = P/A

I = 6.5/0.01

I = 650W/m²

Hence, the intensity of the sunlight in W/m² is 650W/m²

4 0
3 years ago
If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardl
djverab [1.8K]

Answer:

True

Explanation:

It Depends on the order in which each object was plotted, if two connected points objects pass through the same set of three points, the shapes created by each point may be different

7 0
3 years ago
An object in motion does not posses potential energy.<br> O<br> True<br> False
Veronika [31]
True true true true true
6 0
4 years ago
Read 2 more answers
You are jumping on a trampoline and it occurs to you that energy is being transferred as you bounce. (...sounds like your usual
Sever21 [200]

I believe (D) during the second half of the trampoline's movement downward and the first half of the trampoline's movement upward.

But this question is hard to answer. So it can also be C.

4 0
3 years ago
A transformer connected to a 110–(V) (rms) ac line is to supply 10.0 (V) (rms) to a portable electronic device. The load resista
spayn [35]

Answer:

Explanation:

a ) V( primary ) = 100 V

V( secondary ) = 10 V

No of turns ( secondary ) / No of turns ( primary ) = 10 / 100

= 1 / 10

b ) current in secondary

= volt ( secondary ) / resistance

= 10 /6 = 1.67 A

c )

Average power to secondary

= V  ( secondary ) x current ( secondary )

= 10 x 10 / 6

= 16.67 W

d )

Power in primary = power in secondary = 16.67 W

e ) current drawn by ac line ( primary )

Volt ( primary ) x current ( primary ) = power in primary

= 16.67

current ( primary )

= 16.67 / 100

= 0.167 A

5 0
3 years ago
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