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1 answer:
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We're going to remedy it with the parallelogram law.
= one hundred eighty - 30 - 70 = eighty degrees
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
R = three.30 kN, we can conclude now that the value of the ensuing of R is 3.30 kN
sin
/3 = sin(eighty)/three.304 = 63.4 stages
3.3 kN
180 + 33.4 = 213.4 degrees
63.4 - 30 = 33.4
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
R = three.30 kN, we can conclude now that the value of the ensuing of R is 3.30 kN
sin
3.3 kN
180 + 33.4 = 213.4 degrees
63.4 - 30 = 33.4
Answer:
Δx = 39.1 m
Explanation:
- Assuming that deceleration keeps constant during the braking process, we can use one of the kinematics equations, as follows:
where vf is the final velocity (0 in our case), v₀ is the initial velocity
(25 m/s), a is the acceleration (-8.0 m/s²), and Δx is the distance
traveled since the brakes are applied.
- Solving (1) for Δx, we have:
Answer:
In order to hit the same point with the second ball, you should throw it at an angle of 18° above the horizontal.
Explanation:
Horizontal reach formula for projectiles tells us
where is the initial velocity and
the angle above the horizontal.
Since for both shots the reach must be the same, we have
.