Answer:
466 km/h
255°
measured anticlockwise from the east direction
Explanation:
find the resultant velocity of a plane after a crosswind affects its motion. take the positive
x -direction as east, and the positive y -direction as north. The components of the plane's velocity (without wind) are
- <em>upx =</em> 0
- <em>upy = 450 Km/ h</em>
<em>And for the wind.</em>
- <em>uwx = - 120 Km/h</em>
- <em>uwy = 0</em>
<em>The components for the r</em><em>esultant velocity </em><em>of the plane are given by</em>
- <em>ux =upx + uwx = 0 - 120 Km/h = </em><u><em>- 120 Km/h</em></u>
- <em>uy = upy + uwy = - 450 Km/h +0 = </em><u><em>- 450 Km/h</em></u>
<em>The </em><em>magnitude </em><em>of the resultant velocity is</em>
<em />
= 466 km/h
Hope this helps u : )
B) A ladybug crawling forward at constant rate of 2.5 m/s
Answer:
heat, energy that is transferred from one body to another as the result of a difference in temperature. If two bodies at different temperatures are brought together, energy is transferred—i.e., heat flows—from the hotter body to the colder. example: stove
Explanation:
hope this helps
The answer is b.) the momentum before the collision is greater than the momentum after the collision
Answer:
W = 0.842 J
Explanation:
To solve this exercise we can use the relationship between work and kinetic energy
W = ΔK
In this case the kinetic energy at point A is zero since the system is stopped
W = K_f (1)
now let's use conservation of energy
starting point. Highest point A
Em₀ = U = m g h
Final point. Lowest point B
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
mg h = K
to find the height let's use trigonometry
at point A
cos 35 = x / L
x = L cos 35
so at the height is
h = L - L cos 35
h = L (1-cos 35)
we substitute
K = m g L (1 -cos 35)
we substitute in equation 1
W = m g L (1 -cos 35)
let's calculate
W = 0.500 9.8 0.950 (1 - cos 35)
W = 0.842 J