Answer:
The maximum wavelength is 492 nm.
Explanation:
Given that,
Angular separation 
Suppose a telescope with a small circular aperture of diameter 2.0 cm.
We need to calculate the maximum wavelength
Using formula of angular separation


Put the value into the formula

For small angle 



Hence, The maximum wavelength is 492 nm.
Answer:
Q = 4 Q₀
Explanation:
This is an exercise on capacitors, where the capacitance is
C = 
if we apply the given conditions
C = \epsilon_{o} \ \frac{2A}{0.5d}
C = 4 \epsilon_{o} \ \frac{A}{d}
let's call the capacitance Co with the initial values
C₀ = \epsilon_{o} \ \frac{A}{d}
C = 4 C₀
The charge on each plate of a capacitor is
Q = C ΔV
If the potential difference is maintained, the new charge is
Q = 4 C₀ ΔV
let's call
Q₀ = C₀ ΔV
we substitute
Q = 4 Q₀
Answer:
5.09 m/s
Explanation:
Use the height to find the time it takes to land:
y = y₀ + v₀ᵧ t + ½ gt²
0 = 8.0 m + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 1.28 s
Now use the horizontal distance to find the initial velocity.
x = x₀ + v₀ₓ t + ½ at²
6.5 m = 0 m + v₀ (1.28 s) + ½ (0 m/s²) (1.28 s)²
v₀ = 5.09 m/s
The answer your looking for is conduction.
Answer:
2.029×10^-18 J
Explanation:
E=hv
so
E=(3.06×10^15)*(6.63×10^-34)
E=2.029×10^-18 J