Question

A plate having an area of 0.6 m2 is sliding down the inclined plane at 300 to the horizontal with a velocity of 0.36 m/s. There is a cushion of fluid 1.8 mm thick between the plane and the plate. Calculate the viscosity of the fluid if the weight of the plate is 280 N.

Answer 1

Answer:

The viscosity of the fluid is 1.16 N-s/m²

Explanation:

Given that,

Area = 0.6 m²

Angle = 30°

Velocity = 0.36 m/s

Thickness = 1.8 mm

Weight = 280 N

We need to calculate the viscosity of the fluid

Using balance equation

$w\sin\theta=\dfrac{\mu\times v}{t}\times A$

Put the value in the equation

$280\sin30=\dfrac{\mu\times0.36}{1.8\times10^{-3}}\times(0.6)$

$140=\mu\times120$

$\mu=1.16\ N-s/m^2$

Hence. The viscosity of the fluid is 1.16 N-s/m².