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4 years ago

What is the arithmetic mean of the first million odd numbers

1 answer:

8 0

It's 1,000,000:

the sum is 1 + 3 + 5 + ... 1999999 

= 1 + 2 + ... + 2000000 - 2*(1 + ... + 1000000) 

= 2000000*2000001/2 - 2*(1000000*1000001 / 2) 

= 1000000*(2000001 - 1000001) = 1000000000000 (one million million) 

and dividing this by one million to get the average, 

you get one million

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¿Cuál procedimiento resuelve la ecuación 7 (2m + 3) - 5m = 2(4m + 8) + 9 ?

maxonik [38]

Answer:

Step-by-step explanation:

7(2m+3)-5m=2(4m+8)+9

14m+21-5m=8m+16+9

14m-5m-8m+21=16+9

9m-8m+21=25

m+21=25

m=25-21

m=4

6 0

3 years ago

Read 2 more answers

PLEASE HELP ME THANKS!

snow_tiger [21]

Answer:

i think it is B. x^ab, but i could be wrong

Step-by-step explanation:

pemdas so take

x^(a+b)

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6 0

3 years ago

Find the perimeter of rhombus star

Degger [83]

Answer:

$4\sqrt{10}$

Step-by-step explanation:

Perimeter of the rhombus, STAR, is the sum of the length of all it's 4 sides.

The coordinates of its vertices are given as,

S(-1, 2)

T(2, 3)

A(3, 0)

R(0, -1)

Length of each side can be calculated using the distance formula given as $d = \sqrt{x_2 - x_1)^2 + (y_2 - y_1)^2}$

Find the length of each side ST, TA, AR, RS, using the above formula by plugging in the coordinate values (x, y) of each vertices.

$ST = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

S(-1, 2) => (x1, y1)

T(2, 3) => (x2, y2)

$ST = \sqrt{(2 -(-1))^2 + (3 - 2)^2}$

$ST = \sqrt{(3)^2 + (1)^2} = \sqrt{9 + 1} = \sqrt{10}$

$TA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

T(2, 3) => (x1, y1)

A(3, 0) => (x2, y2)

$TA = \sqrt{(3 - 2)^2 + (0 - 3)^2}$

$TA = \sqrt{(1)^2 + (-3)^2} = \sqrt{1 + 9} = \sqrt{10}$

$AR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

A(3, 0) => (x1, y1)

R(0, -1) => (x2, y2)

$AR = \sqrt{(0 - 3)^2 + (-1 - 0)^2}$

$AR = \sqrt{(-3)^2 + (-1)^2} = \sqrt{9 + 1} = \sqrt{10}$

$RS = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

R(0, -1) => (x1, y1)

S(-1, 2) => (x2, y2)

$RS = \sqrt{(-1 - 0)^2 + (2 -(-1))^2}$

$RS = \sqrt{(-1)^2 + (3)^2} = \sqrt{1 + 9} = \sqrt{10}$

$Perimeter = ST + TA + AR + RS$

$Perimeter = \sqrt{10} + \sqrt{10} + \sqrt{10} + \sqrt{10} = 4\sqrt{10}$

4 0

4 years ago

A volume of a coin is 113.04 mm2 what is the approximate of a sphere that has the same height and a circular base with the same

tia_tia [17]

We have been given that the volume of a cone is 113.04 cubic mm. We are asked to find the approximate volume of a sphere that has the same height and a circular base with the same diameter.

We know that volume of cone is $\frac{1}{3}\pi r^2\cdot h$ .