Answer:
Volume of chlorine = 61.943 mL
Explanation:
Given:
Volume of the water in the Pool = 18,000 gal
also,
1 gal = 3785.412 mL
thus,
Volume of water in pool = 18,000 × 3785.412 = 68,137,470 mL
Density of water = 1.00 g/mL
Therefore,
The mass of water in the pool = Volume × Density
or
The mass of water in the pool = 68,137,470 mL × 1.00 g/mL = 68,137,470 g
in terms of million =
or
= 68.13747 g
also,
1 g of chlorine is present per million grams of water
thus,
chlorine present is 68.13747 g
Now,
volume =
or
Volume of chlorine =
or
Volume of chlorine = 61.943 mL
Answer:
For this angular momentum, no quantum number exist
Explanation:
From the question we are told that
The magnitude of the angular momentum is ![L = 6\sqrt{\frac{h}{2 \pi} }](https://tex.z-dn.net/?f=L%20%20%3D%206%5Csqrt%7B%5Cfrac%7Bh%7D%7B2%20%5Cpi%7D%20%7D)
The generally formula for Orbital angular momentum is mathematically represented as
![L = \sqrt{(l * (l + 1)) } * \frac{h}{2 \pi}](https://tex.z-dn.net/?f=L%20%20%3D%20%5Csqrt%7B%28l%20%2A%20%28l%20%2B%201%29%29%20%7D%20%2A%20%20%5Cfrac%7Bh%7D%7B2%20%5Cpi%7D)
Where
is the quantum number
now
We can look at the given angular momentum in this form as
![L = 6\sqrt{\frac{h}{2 \pi} } = \sqrt{36} * \sqrt{\frac{h}{2 \pi}} }](https://tex.z-dn.net/?f=L%20%20%3D%206%5Csqrt%7B%5Cfrac%7Bh%7D%7B2%20%5Cpi%7D%20%7D%20%20%20%20%3D%20%20%5Csqrt%7B36%7D%20%20%2A%20%5Csqrt%7B%5Cfrac%7Bh%7D%7B2%20%5Cpi%7D%7D%20%7D)
comparing this equation to the generally equation for Orbital angular momentum
We see that there is no quantum number that would satisfy this equation
Answer:Protons are positively charged is the correct statement about an atom
I've also corrected the other statements
Atoms contain protons and neutrons in their nucleus
Neutrons posses no charge and are neutral
The nucleon number is the total number of protons and neutrons in a nucleus
Protons are positive
Neutrons are neutral
Electrons are negatively charged