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yKpoI14uk [10]
2 years ago
5

Write the formula for an isotope of oxygen with nine neutrons, including the mass number and the atomic number. Write the answer

in the form XZA using the atomic symbol button in the toolbar, where A is the mass number, Z is the atomic number, and X is the chemical symbol for the unknown element.
Chemistry
1 answer:
Mumz [18]2 years ago
7 0

The formula for an isotope of oxygen with nine neutrons, including the mass number and the atomic number is 17/8 O.

<h3>What is an isotope?</h3>

Isotope is any of two or more forms of an element where the atoms have the same number of protons, but a different number of neutrons within their nuclei.

This means that atoms of isotopes will have the same atomic number but a different mass number.

According to this question, an isotope of oxygen has 9 neutrons. If oxygen has an atomic number of 8, the formula of this particular isotope is as follows: 17/8 O.

Learn more about isotopes at: brainly.com/question/12955625

#SPJ1

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Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

Explanation :

The dissociation of acid reaction is:

                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

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The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

Thus, the equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

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Hope this Helps
Plz mark me as Brainist or verified answer Thanks!!!!!
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