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4 years ago

Need this answered asap (chemistry)

Chemistry

1 answer:

Maru [420]4 years ago

7 0

Answer:

Explanation:

Neutralization reaction is where you add equal moles or quantity of acid and base so that they both neutralize each other or "cancel" each other making the pH to be neutral which is 7. Group B is likely wrong as their pH is 5 which means they added too much acid, if they had equal acid and base their pH would be 7 however since they added more acid, there was still some acid left after the initial neutralization and this acid decreased the pH to 5.

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Two voltaic cells are to be joined so that one will run the other as an electrolytic cell. In the first cell, one half-cell has

vladimir1956 [14]

Au/Cr cell will run as a voltaic cell and Co/Zn cell will run as an electrolytic cell.

<h3>What is an electrolytic cell?</h3>

An electrolytic cell that uses electrical energy to enable a non-spontaneous redox reaction is known as an electrolytic cell.

Certain chemicals can be electrolyzed using electrolytic cells, which are electrochemical cells.

For example, water can be electrolyzed to create gaseous oxygen and gaseous hydrogen with the use of an electrolytic cell.

The following are the three essential parts of electrolytic cells:

Cathode (which is negatively charged for electrolytic cells)

Anode (which is positively charged for electrolytic cells)

Electrolyte

The reactions for each half cell is given by

$Au^{3+}(aq) + 3e^- \rightleftharpoons Au(s)$ ; E° = 1.50 V

$Cr^{3+}(aq) + 3e^- \rightleftharpoons Cr(s)$ ; E° = –0.74 V

$Co^{2+}(aq) + 2e^- \rightleftharpoons Co(s)$ ; E° = –0.28 V

$Zn^{2+}(aq) + 2e^- \rightleftharpoons Zn(s)$ ; E° = –0.76 V

When the Au/Cr cell will run as a voltaic cell and Co/Zn cell will run as an electrolytic cell, the a difference in the voltages is produced

$E^o_{series} = E^o_{Au/Cr} - E^o_{Co/Zn}$ = 2.24 V – 0.48 V = 1.76 V

Learn more about electrolytic cell:

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7 0

1 year ago

kap26 [50]

Answer:

A they share two covalent bonds

8 0

3 years ago

Describe an experiment for the preparation and collection of Oxygen sodium peroxide

vitfil [10]

Answer:

Making oxygen

Oxygen can be made from hydrogen peroxide, which decomposes slowly to form water and oxygen:

hydrogen peroxide → water + oxygen

2H2O2(aq) → 2H2O(l) + O2(g)

The rate of reaction can be increased using a catalyst, manganese(IV) oxide. When manganese(IV) oxide is added to hydrogen peroxide, bubbles of oxygen are given off.

Apparatus arranged to measure the volume of gas in a reaction. Reaction mixture is in a flask and gas travels out through a pipe in the top and down into a trough of water. It then bubbles up through a beehive shelf into an upturned glass jar filled with water. The gas collects at the top of the jar, forcing water out into the trough below.

To make oxygen in the laboratory, hydrogen peroxide is poured into a conical flask containing some manganese(IV) oxide. The gas produced is collected in an upside-down gas jar filled with water. As the oxygen collects in the top of the gas jar, it pushes the water out.

Instead of the gas jar and water bath, a gas syringe could be used to collect the oxygen.

5 0

3 years ago

What is the molarity of the 8.76 g of Na2S dissolved in 0.500 L of solution?

AlexFokin [52]

Answer:

.224 M

Explanation:

To begin, we need to find the molar mass of Na2S

Na=22.99g, S=78.05g

2(22.99)+1(32.07)=78.05

To find Molarity, we use the equation M=moles/Liters of solution

We are given grams, so we must divide by the molar mass of Na2S to find moles.

8.76g Na2S / 78.05g/mol Na2S= .112 moles

Now we use our Molarity equation:

.112 moles Na2S / .500L of solution = .224 M

6 0

2 years ago

What is formed when oxygen and hydrogen unite chemically

gavmur [86]

A. An element is the answer

6 0

4 years ago