Any animals look for steangth mostly because the offspring can probobly onther trait is looks. The male will try to impess the female.
Answer:
2.9 grams.
Explanation:
- From the balanced reaction:
<em>Mg + 1/2O₂ → MgO,</em>
1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.
- We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:
no. of moles of Mg = mass/molar mass = (1.8 g)/(24.3 g/mol) = 0.074 mol.
no. of moles of O₂ = mass/molar mass = (6.0 g)/(16.0 g/mol) = 0.375 mol.
<em>So. 0.074 mol of Mg reacts completely with (0.074/2 = 0.037 mol) of O₂ which be in excess.</em>
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<em><u>Using cross multiplication:</u></em>
1.0 mole of Mg produce → 1.0 mol of MgO.
∴ 0.074 mol of Mg produce → 0.074 mol of MgO.
<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.074 mol)(40.3 g/mol) = <em>2.98 g.</em>
Answer:
Reaction A and B are unfavorable.
Explanation:
Gibbs free energy is an energy which that can be use to convert into useful work.
ΔG°=ΔH°-TΔS°
ΔG°= Gibbs free energy
ΔH° = enthalpy of reaction
T = temperature of eh reaction
ΔS° = Entropy change
- If the Gibbs free energy of the reaction is positive than the reaction will be non spontaneous and the chemical reaction will be not feasible.
- If the Gibbs free energy of the reaction is negative than the reaction will be spontaneous and the chemical reaction will be feasible .
According to given information in the question:
Reaction A and B are non spontaneous as their Gibbs free energy value is positive.hence both are unfavorable.
Answer:
Volume = 746 L
Explanation:
Given that:- Mass of copper(II) fluoride = 175 g
Molar mass of copper(II) fluoride = 101.543 g/mol
The formula for the calculation of moles is shown below:
Thus,
Also,
Considering:
So,,
Given, Molarity = 0.00231 M
So,
<u>Volume = 746 L</u>
Answer:
Gases and particles in Earth's atmosphere scatter sunlight in all directions. Blue light is scattered more than other colors because it travels as shorter, smaller waves. This is why we see a blue sky most of the time.
