You may tell when a solution os formed when the item or particle, such as sugar or salt,
dissolves completely in the solvent, such as water.
Basically, you know when a solution is formed when the material you have placed in the solvent disappears :P
Answer: Theoretical yield of 
produced by 8.96 g of S is 33.6 g
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of 
produce = 3 moles of
Thus 0.28 moles of will produce=
of
Mass of 
Thus theoretical yield of produced by 8.96 g of S is 33.6 g
<h3>The <u>
complete question</u>
would be:</h3>
In a common laboratory experiment in general chemistry, students are asked to determine the relative amounts of benzoic acid and charcoal in a solid mixture. Benzoic acid is relatively soluble in hot water, but charcoal is not. Devise a method for separating the two components in the mixture.
<h3>The <u>
solution</u> for that would be:</h3>
First you put the mixture in hot water and allow the benzoic acid to separate. Next funnel it and then see what's on the funnel paper. Lastly, heat the leftover water and see what's left after it evaporates.
<h3><u>What are laboratory experiments ?</u></h3>
- Using controlled surroundings to test theories, researchers may develop laboratory experiments.
- Laboratories are rooms or specially constructed facilities within buildings that are often found on college and university campuses and are utilized for academic research.
- It's crucial to differentiate between experiments and other kinds of research investigations carried out in lab settings.
- Even if a research study takes place in a lab, it is not always an experiment.
- In order to evaluate causal conclusions regarding the links between independent and dependent variables, laboratory studies, like all genuine experimental designs, use procedures of random assignment of participants and control groups.
To view more about experiments, refer to:
brainly.com/question/17143317
#SPJ4
Answer:
C = 0.08M
Explanation:
molar mass of AlCl3
Al =27
Cl = 35.5
27+3(35.5) =133.5g/mol
n= mass/Molar mass
n =CV
CV = mass/molar mass
C x 500 x 10^-³ = 5/133.5
C x 500 x 10^-³ = 0.04
C = 0.04/500 x 10^-³
C = 0.08M
