1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BabaBlast [244]
3 years ago
5

How many litres of 15% (mass/ volume) copper sulphate solution

Chemistry
2 answers:
givi [52]3 years ago
4 0
Take 15/100 X 75 = The answer
mel-nik [20]3 years ago
4 0

Answer:

dude dont answer my questions dude fucsk you

You might be interested in
What mass of ag2co3 could you produce from 12.7 g agno3 assuming that it is the limiting reagent?
zhenek [66]

10.3 g of  Ag_{2} CO_{3} will produce from 12.7 g AgNO_{3}.

In simple terms, a limiting reagent is a reactant that is completely used up in the reaction. 

It is also referred to as a limiting reactant or limiting agent.

Now, according to the question,

Since it is a limiting reagent, it will react fully. 

The mass of AgCO_{3} that will be produced will be:-

Equivalent mole of AgNO_{3} = Equivalent weight of Ag_{2} CO_{3} = 12.7/169.97 = x*2/274x = 10.3 g. 

Hence, 10.3 g of Ag_{2} CO_{3} will be produced.

It is used to restrict the reaction.

It tells you the estimated amount of compound to be used.

It brings quantitative understanding to chemical reactions.

More information on limiting reagents can be found here :

brainly.com/question/11848702

#SPJ4

7 0
2 years ago
At a constant pressure and amount of gas, how are temperature and volume related?
RSB [31]
The volume is directly proportional to the absolute temperature so the answer is A.
7 0
3 years ago
Electromagnetic radiation at its maximum wavelength is _____.
Fittoniya [83]

Answer:

Option A) Radio waves.

Explanation:

Have a great day.

3 0
3 years ago
Which wave has a disturbance that is perpendicular to the wave motion?
RideAnS [48]

transverse wave

A transverse wave is a wave in which particles of the medium move in a direction perpendicular to the direction that the wave moves.

3 0
3 years ago
what is the specific heat of a substance if 300 j are required to raise the temperature of a 267-g sample by 12 degrees c
slava [35]

Answer : The specific heat of the substance is 0.0936 J/g °C

Explanation :

The amount of heat Q can be calculated using following formula.

Q = m \times C \times \bigtriangleup T

Where Q is the amount of heat required = 300 J

m is the mass of the substance = 267 g

ΔT is the change in temperature = 12°C

C is the specific heat of the substance.

We want to solve for C, so the equation for Q is modified as follows.

C = \frac{Q}{m \times \bigtriangleup T}

Let us plug in the values in above equation.

C = \frac{300J}{267g \times 12 C}

C = \frac{300J}{3204 g C}

C = 0.0936 J/g °C

The specific heat of the substance is 0.0936 J/g°C

3 0
3 years ago
Other questions:
  • Both bacteria and rocks split to give rise to more of their kind. Why are bacteria said to reproduce, but rocks are not? A. Bact
    12·1 answer
  • In an endothermic reaction, heat is absorbed from the surroundings. How does this affect entropy?
    5·2 answers
  • In the compound KHSO4, there is an ionic bond between the
    11·1 answer
  • The physical properties of a solution and the properties of the individual components are
    11·2 answers
  • In general, chemical reactions occur because reactants are trying to become more
    11·1 answer
  • What is the first law of thermodynamics also known as?
    6·1 answer
  • A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.50 grams of aluminum foil in a solut
    14·2 answers
  • Releases energy in the form of ATP
    15·1 answer
  • You are explaining how heat transfers. Your friend insists that when you touch something cold, you become cold
    13·1 answer
  • The molar solubility of cui is 2. 26 × 10-6 m in pure water. Calculate the ksp for cui.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!