What is the formula of the ion formed when phosphorus achieves a noble-gas electron configuration?
2 answers:
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Answer:
a. True
b. True
c. False
d. True
Explanation:
a). A a very low substrate concentration , . Thus according to the Machaelis-Menten equation becomes
Here since the varies directly to the substrate concentration [S], the initial velocity is lower than the maximal velocity. Thus option (a) is true.
b). The Michaelis -Menten kinetics equation states that :
Here the initial velocity changes directly with the substrate concentration as is directly proportional to [S]. But
is same for any particular concentration of the enzymes. Thus, option (b) is true.
c). As the substrate concentration increases, the initial velocity also increases. Thus option (c) is false.
d). Option (d) explains the procedures to estimate the initial velocity which is correct. Thus, option (d) is true.
The volume of oxygen at STP required would be 252.0 mL.
<h3>Stoichiometic problem</h3>The equation for the complete combustion of C2H2 is as below:
The mole ratio of C2H2 to O2 is 2:5.
1 mole of a gas at STP is 22.4 L.
At STP, 100.50 mL of C2H2 will be:
100.50 x 1/22400 = 0.0045 mole
Equivalent mole of O2 according to the balanced equation = 5/2 x 0.0045 = 0.01125 moles
0.01125 moles of O2 at STP = 0.01125 x 22400 = 252.0 mL
Thus, 252.0 mL of O2 gas will be required at STP.
More on stoichiometric problems can be found here: brainly.com/question/14465605
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