Answer:
The answer is
<h2>0.4 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
![density = \frac{mass}{volume}](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20)
From the question
mass of wood = 120 g
volume = 300 cm³
So the density of the wood is
![density = \frac{120}{300} \\ = \frac{12}{30} = \frac{2}{5}](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7B120%7D%7B300%7D%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B12%7D%7B30%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B5%7D%20)
We have the final answer as
<h3>0.4 g/cm³</h3>
Hope this helps you
Answer: On the basis of electrical conductivity, materials are classified as conductors, semi-conductors and non-conductors. Conductors : Substances through which electricity can easily pass through are known as conductors. ... For example, glass, wood are non-conductors. Wood is used to make tables, desks etc.
Answer:
Explanation:
Salicylic Acid:
Salicylic Acid is an hydroxy acid that is found as a natural compound in plants. It's IUPAC name is 2-hydroxybenzoic acid. Salicylic acid has an odorless white to light tan solid color. It sinks and mixes very slow with water.
Acid: An acid is a substance that produce hydrogen ion or proton when dissolved in water
Base: A base is a substance that will neutralize an acid to yield salt and water
Conjugate Base: This is a substance formed when an acid loses an hydrogen ion or proton when it dissolved in water.
Conjugate Acid: This is a substance formed when a base accept a proton from from any acid, when it dissolved in water.
Reaction between salicylic acid and potassium hydroxide
HOC₆H₄COOH(aq) + KOH(aq) ⇄ HOC₆H₄COOK(aq) + H₂O(l)
Acid ⇒ HOC₆H₄COOH (salicylic acid)
Base ⇒ KOH (potassium hydroxide)
Conjugate acid ⇒ H₂O (water)
conjugate base ⇒ HOC₆H₄COOK ( 2-hydroxypotasium benzoate)
c well actually I remember being tought this but I cant remember it 100
Answer:
56.9 mmoles of acetate are required in this buffer
Explanation:
To solve this, we can think in the Henderson Hasselbach equation:
pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])
To make the buffer we know:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
We know that Ka from acetic acid is: 1.8×10⁻⁵
pKa = - log Ka
pKa = 4.74
We replace data:
5.5 = 4.74 + log ([acetate] / 10 mmol)
5.5 - 4.74 = log ([acetate] / 10 mmol)
0.755 = log ([acetate] / 10 mmol)
10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)
5.69 = ([acetate] / 10 mmol)
5.69 . 10 = [acetate] → 56.9 mmoles