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HACTEHA [7]
4 years ago
6

How is a mole like a dozen?

Chemistry
2 answers:
nasty-shy [4]4 years ago
7 0

The mole is a unit for counting 6.02 1023 representative particles.

The dozen is used to count 12 items

12345 [234]4 years ago
3 0

Answer:

Answer in explanation.

Explanation:

The mole is a unit for counting 6.02 1023 representative particles. The dozen is used to count 12 items.

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Students working in lab accidentally spilled 17 l of 3.0 m h2so4 solution. they find a large container of acid neutralizer that
jek_recluse [69]

Answer is: 8568.71 of baking soda.

Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.

V(H₂SO₄) = 17 L; volume of the sulfuric acid.

c(H₂SO₄) = 3.0 M, molarity of sulfuric acid.

n(H₂SO₄) = V(H₂SO₄) · c(H₂SO₄).

n(H₂SO₄) = 17 L · 3 mol/L.

n(H₂SO₄) = 51 mol; amount of sulfuric acid.

From balanced chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 :2.

n(NaHCO₃) = 2 · 51 mol.

n(NaHCO₃) = 102 mol, amount of baking soda.

m(NaHCO₃) = n(NaHCO₃) · M(NaHCO₃).

m(NaHCO₃) = 102 mol · 84.007 g/mol.

m(NaHCO₃) = 8568.714 g; mass of baking soda.

8 0
3 years ago
Suppose you were calibrating a 100.0 ml volumetric flask using distilled water. the flask temperature was at 20°c, and you assum
kicyunya [14]
The density of water at 12°C is lower than the density of water at 20°C.

Now density is related to volume as per: density = mass / volume =>

mass = volume * density.

So, the greaer the density the higher the mass of the same volume of water.

Therefore, 100.0 ml of water at 12°C has a mass greater than 100.00 ml of water at 20 °C.
4 0
4 years ago
How many electrons make up an octet?<br> 
soldi70 [24.7K]
It’s 8 electrons. “octa” means 8
5 0
3 years ago
A hot piece of copper was dropped into 155 g of water at 23.6 °C and 2,100 J of energy was transferred to the water. What is the
BlackZzzverrR [31]

Answer:

26.8 °C

Explanation:

Step 1: Given and required data

  • Mass of water (m): 155 g
  • Energy transferred to the water (Q): 2100 J
  • Initial temperature of the water (T₂): 23.6 °C
  • Final temperature of the water (T₁): ?
  • Specific heat of water (c): 4.184 J/g.°C

Step 2: Calculate the final temperature of the water

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = 2100 J/(4.184 J/g.°C) × 155 g + 23.6 °C = 26.8 °C

5 0
3 years ago
What is the percent of hydrogen by mass in HNO3?
Brilliant_brown [7]

the percent of hydrogen by mass in HNO3 is 1.600%

8 0
3 years ago
Read 2 more answers
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