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valentinak56 [21]
3 years ago
11

Assign each species to the expression that most accurately describes the basic units of that substance. categories: single atoms

- Copper, Helium, Ag, diatomic molecules -Iodine, Fluorine, Br2 molecules -No2, KMnO4, formula units - C3H8, MgCl2, HgBr2, Ba(OH)2 this is what i think it is but not sure.
Chemistry
2 answers:
Lelechka [254]3 years ago
8 0

ATOMS - copper, helium, silver

MOLECULES - iodine, fluorine, bromine, NO₂, C₃H₈

FORMULA UNITS - KMnO₄, MgCl₂, HgBr₂, Ba(OH)₂

<h3>Further Explanation</h3>

The basic units or representative units of a substance may be atoms, ions, molecules, or formula units.

  • If the substance are elements in monatomic form, their representative unit is  "atoms". If they are diatomic elements, then their representative unit is "molecule".
  • If the substance is a compound, the representative unit depends on the kind of bonding. If the substance is ionic in nature, its representative unit is called a "formula unit". If the substance is covalent or molecular, the representative unit is also called "molecule".
  • Recall that ionic compounds are substances that are made up of metallic and nonmetallic elements that are chemically bonded. Covalent or molecular compounds are those that are only composed of chemically bonded nonmetal elements.
  • If pertaining to the component ions of an ionic compound, the representative particles are called "ions".

Therefore, the substances in the problem may be grouped to the following representative particles:

ATOMS - copper, helium, silver

MOLECULES - iodine, fluorine, bromine, NO₂, C₃H₈

FORMULA UNITS - KMnO₄, MgCl₂, HgBr₂, Ba(OH)₂

<h3>LEARN MORE</h3>
  • Learn more about Compounds brainly.com/question/8968140
  • Learn more about Stoichiometry brainly.com/question/12980009

Keywords: representative units, atoms, molecules, formula units

Temka [501]3 years ago
6 0
Atoms are the smallest form of the substance. examples of atoms are in elemental forms such as copper, helium, silver. Diatomic molecules are made up of identical atoms. Examples are I2.. F2 and Br2. Formula units are those compounds that are made up of two or more elements such as -No2, KMnO4,<span>C3H8, MgCl2, HgBr2, Ba(OH)2</span>
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The ka of hypochlorous acid (hclo) is 3.0 ⋅ 10−8 at 25.0 °c. calculate the ph of a 0.0375m hypochlorous acid solution.
Scrat [10]
We can set up an ICE table for the reaction:                      
                      HClO          H+     ClO-
Initial              0.0375       0        0
Change         -x               +x      +x
Equilibrium    0.0375-x     x        x

We calculate [H+] from Ka:     
     Ka = 3.0x10^-8 = [H+][ClO-]/[HClO] = (x)(x)/(0.0375-x)

Approximating that x is negligible compared to 0.0375 simplifies the equation to         
     3.0x10^-8 = (x)(x)/0.0375     
     3.0x10^-8 = x2/0.0375     
     x2 = (3.0x10^-8)(0.0375) = 1.125x10^-9     
     x = sqrt(1.125x10^-9) = 0.0000335 = 3.35x10^-5 = [H+]
in which 0.0000335 is indeed negligible compared to 0.0375.

We can now calculate pH:     
     pH = -log [H+] = - log (3.35 x 10^-5) = 4.47
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3 years ago
Phosphate buffers are commonly used in biological research. If a small amount of strong acid is added to a buffer solution that
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Answer:

A) [H3PO4] will increase, [KH2PO4] will decrease, and pH will slightly decrease.

Explanation:

A buffer is a solution which resists changes to its pH when a small amount of acid or base is added to it.

Buffers consist of a weak acid (HA) and its conjugate base (A–) or a weak base and its conjugate acid. Weak acids and bases do not completely dissociate in water, and instead exist in solution as an equilibrium of dissociated and undissociated species. When a small quantity of a strong acid is added to a buffer solution, the conjugate base, A-, reacts with the hydrogen ions from the added acid to form the weak acid and a salt thereby removing the extra hydrogen ions from the solution and keeping the pH of the solution fairly constant. On the other hand, if a small quantity of a strong base is added to the buffer solution, the weak acid dissociates further to release hydrogen ions which then react with the hydroxide ions of the added base to form water and the conjugate base.

For example, if a small amount of strong acid is added to a buffer solution that is 0.700 M H3PO4 and 0.700 M KH2PO4, the following reaction is obtained:

KH₂PO₄ + H+ ----> K+ + H₃PO₄

Therefore, [H₃PO₄] will increase, [KH₂PO₄] will decrease, and pH will slightly decrease.:

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