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3 years ago

If f(3) = 15 and f(5) = 45, which of the following could be f(x)?

1 answer:

5 0

F(x) = 2x² - x
f(3) = 2(3)² - 3
f(3) = 2(9) - 3
f(3) = 18 - 3
f(3) = 15

f(x) = 2x² - x
f(5) = 2(5)² - 5
f(5) = 2(25) - 5
f(5) = 50 - 5
f(5) = 45

The answer is C.

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For what value(s) of k will the relation not be a function?

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Answer:

See below

Step-by-step explanation:

The relation is not a function when x -value is same but y- values are different.

k^2 = 4k
k = 0, k = 4

k^2 - 5k = k + 7
k^2 - 6k = 7
k^2 - 6k + 9 = 16
k - 3 = 4 ⇒ k = 7
k - 3 = -4 ⇒ k = -1

k^3 - 5k^2 + 3k = -k
k^3 - 5k^2 + 4k = 0
k(k^2 - 5k + 4) = 0
k = 0, k = 1, k = 4

|k + 1| + 2 = 8
|k + 1| = 6
k = 5, k = -7

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3 years ago

Two towns on a map are 2 1/4 inches apart.the actual distance between the towns is 45 miles. Which of the following could be the

Leona [35]

Answer:

what are the answer choices

Step-by-step explanation:

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3 years ago

A teenager’s heart pumps an average of 7200 L of blood every 24 hours. What is the rate of change of volume of blood?

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Answer:

300L per hour

Step-by-step explanation:

The rate of change of volume of blood pumped by the teenager's heart expresses the volume of blood pumped with respect to hour.

Rate of change of volume of blood = $\frac{volume of blood}{time}$

= $\frac{7200L}{24}$

= 300L/hour

The rate of change of volume of blood by the teenager's heart is 300 litres per hour. This implies that his/ her heart pumps 300 litres of blood every hour.

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3 years ago

34% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

10 student are sampled, so $n = 10$

34% of college students say they use credit cards because of the rewards program, so $\pi = 0.34$

(a) exactly two

This is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than two

This is $P(X > 2)$ .

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

$P(X \leq 2) + P(X > 2) = 1$

$P(X > 2) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157$

$P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838$

$P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162$

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573$

$P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320$

$P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434$

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82$

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0

3 years ago

What property is 8 (m - 4 ) = 8 (m) - 8(4)

Darina [25.2K]

It is the <span>The </span>Distributive property

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