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3 years ago

How many atoms of hydrogen are present in 7.63 g of ammonia? please help me ??

1 answer:

3 0

The atoms of hydrogen that are present in 7.63 g of ammonia(NH3)

find the moles of NH3 =mass/molar mass
7.63 g/ 17 g/mol = 0.449 moles

since there is 3 atoms of H in NH3 the moles of H = 0.449 x 3 = 1.347 moles

by use of 1 mole = 6.02 x10^23 atoms
what about 1.347 moles

= 1.347 moles/1 moles x 6.02 x10^23 atoms = 8.11 x10^23 atoms of Hydrogen

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A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128

alisha [4.7K]

Answer: The final temperature of both the weight and the water at thermal equilibrium is $50.26^{o}C$ .

Explanation:

The given data is as follows.

mass = 7.62 g, $T_{2} = 10.8^{o}C$

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

q = $mC \times \Delta T$

= $7.62 g \times 4.184 J/^{o}C \times (52.3 - T)$

Now, heat gained by lead will be calculated as follows.

q = $mC \times \text{Temperature change of lead}$

= $2.04 \times 0.128 \times (T - 11.0)$

According to the given situation,

Heat lost = Heat gained

$7.62 g \times 4.184 J/^{o}C \times (52.3 - T)$ = $2.04 \times 0.128 \times (T - 11.0)$

T = $50.26^{o}C$

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is $50.26^{o}C$ .

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What is the pH of a 6.4*10-10 m oh- solution?

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Which statement about atoms and molecules is

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Elements always exist as pair of atoms called molecules .

Explanation:-

The material which has only one types of similar atoms called element .
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