How many atoms of hydrogen are present in 7.63 g of ammonia? please help me ??

1 answer:

3 0

The atoms of hydrogen that are present in 7.63 g of ammonia(NH3)

find the moles of NH3 =mass/molar mass
7.63 g/ 17 g/mol = 0.449 moles

since there is 3 atoms of H in NH3 the moles of H = 0.449 x 3 = 1.347 moles

by use of 1 mole = 6.02 x10^23 atoms
what about 1.347 moles

= 1.347 moles/1 moles x 6.02 x10^23 atoms = 8.11 x10^23 atoms of Hydrogen

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