Using the answer from the first part, we know that 2.957 moles of bismuth have formed. Moreover, the molar ratio between bismuth and carbon monoxide is:
2 : 3
Using the method of ratios,
2 : 3
2.957 : CO
CO = (3 * 2.957) / 2
CO = 4.4355
4.436 moles of carbon monoxide will be formed
<span>The answer is 2:3. Because the lowest common denominator of 2 and 3 is 6, we find that for every 2 Fe3+ ions, we would need 3 O2- ions to neutralize the charge. The other answers do not fit this idea, as the math doesn't then add up to come to a neutral charge.</span>
Species that have the same number of electrons or the same electronic structure.
Answer:
Dienes are alkenes that contain two carbon-carbon double bonds, so they have the same properties as these hydrocarbons.
In the attached file are the two reactions of dienes production.
Explanation:
Two ways to obtain dienes are as follows:
-Reaction of oxidative dehydrogenation of an alkane, is an exothermic process and occurs at lower temperatures, diene and water are formed, generating greater conversion at lower temperature levels.
-Dehydration of primary alcohols. The treatment of alcohols with acid at elevated temperatures produces dienes due to water loss. For example, heating ethanol in the presence of sulfuric acid produces ethene by the loss of a water molecule.
Answer:
- According to the law <br> Mass of reactants = mass of product, here <br> `underset(10 g)(CaCO_(3))rarr underset(4.4 g)(CO_(2))+underset(x)(CaO)` <br> Hence, x = 10 g - 4.4 g = 5.6 g <br> Which is mass of CaO.d
- In the first compound <br> Hydrogen = 5.93 % <br> Oxygen = `(100-5.93)% = 94.07 %` <br> In the second compound <br> Hydrogen = 11.2 % <br> Oxygen `= (100-11.2)%=88.8%` <br> In the first compound the number of parts by mass of oxygen that combine with one part by mass of hydrogen `=(94.07)/(5.93)=15.86` parts ...
- (The ratio of Cu combining with fixed weight of oxygen in black and red oxide is 1 : 2 respectively. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.) {Check something more in the above attachment!}
- Refer to the above attachment
Explanation:
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