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Romashka [77]
3 years ago
12

A magnetic hockey puck (0.40 kg) hits another hockey puck (0.40 kg) at rest and both travel together to the right at 8.0 m/s. Ho

w fast was the first hockey puck initially moving?
m/s
Physics
2 answers:
creativ13 [48]3 years ago
8 0

<u>Answer</u>

= 16 m/s


<u>Explanation</u>

The law conservation of energy states that, momentum before collision is equal to momentum after collision.

m₁v₁ = m₂v₂

momentum before collision = (0.40 × v) + (0.40 × 0)

= 0.4v Km/s

momentum after collision = (0.40+0.40) × 8.0

= 0.8 ×8.0

= 6.4 Km/s

m₁v₁ = m₂v₂

0.4v Km/s = 6.4 Km/s

v = 6.4/0.4

= 16 m/s


DaniilM [7]3 years ago
6 0
This problem can be solved through the Inelastic Collision Formula:
mass1 x in.velocity1 + mass2 x in.velocity2 = mass1+mass2 (final velocity)

Substituting the values, we have:
0.40 kg x in.velocity1 + 0.40 kg x 0 m/s = 0.80 kg (8.0m/s)

Solving for the unknown initial velocity of the moving hockey puck we have:
in.velocity1 = (6.4 kgm/s - 0) / 0.40 kg
= 16 m/s 
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In the nuclear fission process mass is converted into energy. Determine the total mass that must be converted to energy in one y
brilliants [131]

Answer:

1) Mass that needs to be converted at 100% efficiency is 0.3504 kg

2) Mass that needs to be converted at 30% efficiency is 1.168 kg

Explanation:

By the principle of mass energy equivalence we have

E=mc^{2}

where,

'E' is the energy produced

'm' is the mass consumed

'c' is the velocity of light in free space

Now the energy produced by the reactor in 1 year equals

Energy=Power\times time\\\\\therefore Energy=1\times 10^{9}\times 365\times 24\times 3600\\\\Energy=31.536\times 10^{15}Joules

Thus the mass that is covertred at 100% efficiency is

mass=\frac{Energy}{c^{2}}\\\\mass=\frac{31.536\times 10^{15}}{(3\times 10^{8})^{2}}\\\\mass=\frac{31.536\times 10^{15}}{9\times 10^{16}}\\\\\therefore mass=0.3504kg

Part 2)

At 30% efficiency the mass converted equals

mass|_{30}=\frac{mass|_{100}}{0.3}\\\\mass|_{30}=\frac{0.3504}{0.3}\\\\mass|_{30}=1.168kg

8 0
3 years ago
A space shuttle with a mass of approximately 7.08 E5 kg is sitting on the launch pad. What would be the weight of the space shut
Afina-wow [57]

The weight of the shuttle is 6.94\cdot 10^6 N

Explanation:

The weight of an object on Earth is the gravitational force exerted by the Earth on the object.

The magnitude of the weight of an object is given by:

W=mg

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity on Earth's surface

And the direction is downward (towards the Earth's centre).

For the shuttle in this problem, its mass is

m=7.08\cdot 10^5 kg

So, its weight is

W=(7.08\cdot 10^5)(9.8)=6.94\cdot 10^6 N

Note that while the mass of an object (m) does not change, its weight (W) changes according to the location, since the value of g can be different at different location (for example, on the Moon, the value of g is about 1/6 the value of g on the Earth).

Learn more about weight and forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

6 0
2 years ago
An atom of gadolinium has an atomic number of 64 and a mass number of 154. how many electrons, protons, and neutrons does it con
Svetllana [295]
No. of protons = atomic number = 64
no. of neutrons = mass no. - no. of protons= 154 -64 = 90
no. of electrons = no. of protons = 64
5 0
3 years ago
An engineer weighs a sample of mercury (ρ = 13.6 × 103 kg/m3 ) and finds that the weight of the sample is 6.0 n. what is the sam
Amanda [17]
Given:
ρ = 13.6 x 10³ kg/m³, density of mercury
W = 6.0 N, weight of the mercury sample
g = 9.81 m/s², acceleration due to gravity.

Let V =  the volume of the sample.
Then
W = ρVg
or
V =  W/(ρg)
   = (6.0 N)/[(13.6 x 10³ kg/m³)*(9.81 m/s²)]
   = 4.4972 x 10⁻⁵ m³

Answer: The volume is 44.972 x 10⁻⁶ m³
5 0
2 years ago
An airplane is at rest on a runway. It accelerates at 10 m/s2 for 15 seconds. How fast is it now traveling?​
KATRIN_1 [288]

Answer:

150

Explanation:

v = at

v = 10(15)

v = 150 m/s

6 0
3 years ago
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