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Romashka [77]
3 years ago
12

A magnetic hockey puck (0.40 kg) hits another hockey puck (0.40 kg) at rest and both travel together to the right at 8.0 m/s. Ho

w fast was the first hockey puck initially moving?
m/s
Physics
2 answers:
creativ13 [48]3 years ago
8 0

<u>Answer</u>

= 16 m/s


<u>Explanation</u>

The law conservation of energy states that, momentum before collision is equal to momentum after collision.

m₁v₁ = m₂v₂

momentum before collision = (0.40 × v) + (0.40 × 0)

= 0.4v Km/s

momentum after collision = (0.40+0.40) × 8.0

= 0.8 ×8.0

= 6.4 Km/s

m₁v₁ = m₂v₂

0.4v Km/s = 6.4 Km/s

v = 6.4/0.4

= 16 m/s


DaniilM [7]3 years ago
6 0
This problem can be solved through the Inelastic Collision Formula:
mass1 x in.velocity1 + mass2 x in.velocity2 = mass1+mass2 (final velocity)

Substituting the values, we have:
0.40 kg x in.velocity1 + 0.40 kg x 0 m/s = 0.80 kg (8.0m/s)

Solving for the unknown initial velocity of the moving hockey puck we have:
in.velocity1 = (6.4 kgm/s - 0) / 0.40 kg
= 16 m/s 
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Read 2 more answers
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sergij07 [2.7K]

Answer:

The  magnetic field is  B = 0.0764 \ T

Explanation:

From the question we are told that  

    The mass of the metal is  m  =  0.210 \ kg

     The current is  I  =  11.0 \ A

      The distance between the rail(length of the rod ) is  d  =  0.490 \ m

      The coefficient of kinetic friction is  \mu_k  =  0.200

Generally the magnetic force is mathematically represented as

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Given that the rod is moving at a constant velocity, it

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Where F_k is the kinetic frictional force which is mathematically represented as

       F_k  =  \mu_k  *  m *  g

So

    B *  I  *  d =  \mu_k  * m * g

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substituting values

=>   B =  \frac{0.200  * 0.210  * 9.8 }{ 11  *  0.490 }

=>   B = 0.0764 \ T

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hence we can see that upon increase in altitude the value of 'g' goes on decreasing.

5 0
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