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3 years ago

Solve the equation for xx. For each step, describe the operation used to convert the equation.

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

8 0

Answer:

x = 6

Step-by-step explanation:

Equation given in the question:

3x − [ 8 − 3(x−1) ] = x + 19

Now,

multiplying the term (3(x-1)) in the equation, we get

⇒ 3x - [ 8 - 3x -3 × (-1)] = x + 19

⇒ 3x - [ 8 -3x +3 ] = x + 19

⇒ 3x - [ 11 -3x ] = x + 19

now,

multiplying opening the bracket [11 - 3x]

⇒ 3x - 11 - (-3x) = x + 19

⇒ 3x - 11 + 3x = x + 19

on adding the terms with same coefficient 'x' on LHS

⇒ (3 + 3)x - 11 = x + 19

⇒ 6x - 11 = x + 19

taking -11 to the RHS

⇒ 6x = x + 19 + 11

⇒ 6x = x + 30

subtracting x both the sides

⇒ 6x - x = x + 30 - x

5x = 30

dividing the both sides by 5

$\frac{5x}{5}= \frac{30}{5}$

therefore,

x = 6

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3 years ago

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timurjin [86]

Answer:

The answer is 54.6.

9.1(6)+8.7(7)=54.6+60.9

Step-by-step explanation:

Given:

9.1(6)+8.7(7)=_+60.9

Now, to solve it:

9.1(6)+8.7(7)=_+60.9

Let the _be x.

So, we remove parenthesis first that makes it multiply with the number next to it:

$9.1\times 6+8.7\times 7=x+60.9$

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4 years ago

A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo

defon

Answer:

a) The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

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And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

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And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

$X \sim Unif (a= 10, b =12)$

Part a

The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

Part b

For this case we want this probability:

$P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

Part c

For this case we want this probability:

$P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

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4 years ago

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Answer:

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Step-by-step explanation:

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