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Tamiku [17]
3 years ago
10

You are given three beakers of unknown liquids. One beaker contains pure water. One contains salt water. One contains sugar wate

r. Without tasting the liquids, how could you identify the liquid in each beaker?
Chemistry
2 answers:
Verdich [7]3 years ago
6 0

Answer: The density and electrical conductivity of the solutions can be measured

Explanation:

We could get three beakers and measure the mass of the solution by subtracting the mass of the beaker from mass of solution + beaker. After that, we use a measuring cylinder to determine the volumes of the three solutions. The density is then obtained from:

Density= mass/volume

The density of pure water is always 1gcm-3.

Measurement of electrical conductivity will distinguish between the salt and sugar solutions. The salt solution will have high electrical conductivity. The solution with the highest electrical conductivity is the salt solution while the solution with the least electrical conductivity is the sugar solution. Sugar does not conduct electricity in solution because it does not contain ions.

sergeinik [125]3 years ago
5 0
Trick question: you just stated everything in the beakers.
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n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 97,2 g ÷ 18 g/mol.
n(H₂O) = 5,4 mol.
N(H₂O) = n(H₂O) · Na.
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4 years ago
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3 years ago
How many Liters of a 4.5 M HCL solution can be prepared by using 250.0 mL of a 12.0 M HCl solution?
netineya [11]

Answer:

0.667 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial concentration (C₁) = 12 M

Final concentration (C₂) = 4.5 M

Final volume (V₂) =?

The final volume of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

12 × 250 = 4.5 × V₂

3000 = 4.5 × V₂

Divide both side by 4.5

V₂ = 3000 / 4.5

V₂ = 667 mL

Finally, we shall convert 667 mL to L. This can be obtained as follow:

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3 0
3 years ago
To what temperature was 32.0L of gas at 2°C be heated for it to occupy 1.00*10^2L at the same pressure?
jolli1 [7]

Answer:

T₂ = 859.4 K

Explanation:

Given data:

Initial volume of gas = 32.0 L

Initial temperature = 2°C (2 + 273 = 275 k)

Final temperature = ?

Final volume = 1.00 ×10²L

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ /V₁  

T₂ = 1.00 ×10²L × 275 K / 32.0 L

T₂ = 27500 L.K / 32.0 L

T₂ = 859.4 K

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