600,000 mm if im not mistaken.
Answer:
88.50 %
The balance chemical equation is as follow,
2 H₂ + O₂ → 2 H₂O
Step 1: Find the limiting reactant;
According to eq.
4.032 g (2 mole) H₂ reacts with = 32 g (1 mole) of O₂
So,
11 g of H₂ will react with = X g of O₂
Solving for X,
X = (11 g × 32 g) ÷ 4.032 g
X = 87.301 g of O₂
Therefore, H₂ is the limiting reactant as O₂ is present in excess.
Step 2: Calculating %age Yield;
According to eq.
4.032 g (2 mole) H₂ produces = 36.032 g (1 mole) of H₂O
So,
11 g of H₂ will react with = X g of H₂O
Solving for X,
X = (11 g × 36.032 g) ÷ 4.032 g
X = 98.301 g of H₂O
So,
Actual Yield = 87 g
Theoretical Yield = 98.301 g
Using formula = Actual Yield / Theoretical Yield × 100
= 87 g / 98.301 × 100
= 88.50 %
Answer:
A) 1
B) 2.5
C) 3.32
Explanation:
The possibility of n=1 is not achievable in 20 minutes and 30 minutes as calculated n=1 for 10 minutes. The same conversion cannot be achieved for the rest of the time which is impossible as 75% conversion and it cannot be achieved at 10 min and 20 min at the same time
A) what is the order of the reaction if it takes 10 minutes to reach 75% conversion
= n ( order ) = 1
B) what is the order of reaction if it takes 20 minutes to reach 75% conversion
= n ( order ) ≈ 2.5
C) what is the order of reaction if it takes 30 minutes to reach 75% conversion
= n ( order ) ≈ 3.32
attached below is a detailed solution
Answer:
- <u>The researcher's can safely raise the fish before reaching the 170 m depth.</u>
Explanation:
Assuming constant temperature, you can use Boyle's law:

Where:
- p₁ is the pressure at 500 m depth = 50.57 atm
- p₂ is the unknown pressure
- V₂ is the maximum volume that the fish's swim bladder can hold = 0.34 liters
Then, determine p₂:


From the table, there is a linear relationship between pressure (atm) and water depth (m).
The slope of the linear function is about 0.099:
- (50 - 40)/(100-50) = 0.099
The y-intercept is 1.00 (the point 0, 1.00).
Then, the linear function is: Pressure = 1 + 0.099×depth
Now you can find the depth at wich the pressure is 17.85 atm
- 17.85atm = 1.00atm + 0.099×depth
- depth = (17.85 atm - 1.00atm) / 0.099 = 170.2 m ≈ 170 m
Hence, the fish's swimm bladder will ruputure at 170m.