Answer:
A Fridiel craft catalyst will convert benzene to acetophenone.
Permanganate catalyst can be used to convert toluene to acetophenone.
Explanation:
Benzene can be reduced to acetophenone by the addition of anhydrous aluminium chloride, AlCl₃
The mechanism is as follows:
Benzene + Acetyl choloride → acetophenone
To convert toluene to acetophenone, the following steps are necessary:
- Oxidation of Toluene to Benzoic acid.
This is done by refluxing toluene with alkaline potassium permanganate (KMnO₄+ Na₂CO₃).
-
Benzoic acid is converted to Benzoyl chloride by treating with thioyl chloride and heating at about 80 ⁰C.
-
Benzoyl chloride is treated with methyl lithium to form Acetophenone.
Answer is "The salt Bridge"
Explanation:
During the spontaneous reaction in Voltaic Cell, the balance of ions get disturb due to increase in concentration of negative charge in one half cell and positive charge in another. In order to keep balance the charges in cell, concentration of ions on both sides and overall neutrality of the system, a U-shape tube filled with inert electrolyte is connected to both half cells. The electrolyte migrates in such a way that the charges of solution in cells keep constant.
Answer:the second one
Explanation:,Hydrogen bonding is a special type of dipole-dipole attraction between molecules ,not a covalent bond to a hydrogen atom. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom.
Answer:
Mass of calcium carbonate decompose 49g.
Explanation:
Given data:
Mass of CaO = 28.00 g
Mass of CO₂ = 21.97 g
Mass of calcium carbonate decompose = ?
Solution:
Chemical equation:
CaCO₃ → CO₂ + CaO
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 21.97 g / 44 g/mol
Number of moles = 0.49 mol
Number of moles of CaO:
Number of moles = mass/molar mass
Number of moles = 28.00 g / 56.1 g/mol
Number of moles = 0.49 mol
Now we will compare the moles of CaCO₃ with CaO and CO₂ .
CO₂ : CaCO₃
1 : 1
0.49 : 0.49
CaO : CaCO₃
1 : 1
0.49 : 0.49
Mass of CaCO₃ decompose:
Mass = number of moles × molaer mass
Mass = 0.49 mol × 100.1 g/mol
Mass = 49 g
