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2 years ago

Why do fire accidents take place in mines? What are the diseases caused?

Chemistry

1 answer:

Lorico [155]2 years ago

7 0

Answer:

Mining accidents can occur from a variety of causes, including leaks of poisonous gases such as hydrogen sulfide or explosive natural gases, especially firedamp or methane, dust explosions, collapsing of mine stopes.Dust: Very fine mineral dust particles from blasting and drilling can accumulate in the lungs, causing a disease called pneumoconiosis. An irreversible, disabling form of this disease called silicosis can occur when a miner inhales excessive amounts of crystalline silica, or quartz

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What atom has 35 protons and 47 neutrons ?

svet-max [94.6K]

Answer:

Bromine

Explanation:

6 0

2 years ago

Read 2 more answers

How many moles of oxygen are needed for the complete combustion of 29.2 grams of acetylene?

podryga [215]

Moles of Oxygen= 2.8075 moles

<h3>Further explanation</h3>

Given

29.2 grams of acetylene

Required

moles of Oxygen

Solution

Reaction(Combustion of Acetylene) :

2 C₂H₂ (g) + 5 O₂ (g) ⇒ 4CO₂ (g) + 2H₂O (g)

Mol of Acetylene :

= mass : MW Acetylene

= 29.2 g : 26 g/mol

= 1.123

From equation, mol ratio of Acetylene(C₂H₂) : O₂ = 2 : 5, so mol O₂ :

= 5/2 x mol C₂H₂

= 5/2 x 1.123

= 2.8075 moles

7 0

2 years ago

How long does it take an object to travel 50m at a rate of 8 m/s?

Harman [31]

Answer:

6.25s

Explanation:

time = distance / speed

time = 50 / 8

time = 6.25s

7 0

2 years ago

At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction:

Butoxors [25]

Answer: The equilibrium concentration of ICl is 0.27 M

Explanation:

We are given:

Initial moles of iodine gas = 0.45 moles

Initial moles of chlorine gas = 0.45 moles

Volume of the flask = 2.0 L

The molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}$

Initial concentration of iodine gas = $\frac{0.45}{2}=0.225M$

Initial concentration of chlorine gas = $\frac{0.45}{2}=0.225M$

For the given chemical equation:

$2ICl(g)\rightarrow I_2(g)+Cl_2(g);K_c=0.11$

As, the initial moles of iodine and chlorine are given. So, the reaction will proceed backwards.

The chemical equation becomes:

$I_2(g)+Cl_2(g)\rightarrow 2ICl(g);K_c=\frac{1}{0.11}=9.091$

Initial: 0.225 0.225

At eqllm: 0.225-x 0.225-x 2x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[ICl]^2}{[Cl_2][I_2]}$

Putting values in above equation, we get:

$9.091=\frac{(2x)^2}{(0.225-x)\times (0.225-x)}\\\\x=0.135,0.668$

Neglecting the value of x = 0.668 because equilibrium concentration cannot be greater than the initial concentration

So, equilibrium concentration of ICl = 2x = (2 × 0.135) = 0.27 M

Hence, the equilibrium concentration of ICl is 0.27 M

6 0

2 years ago

At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. part a if the initial concentration of no

luda_lava [24]

Answer:

[NO] = 1.72 x 10⁻³ M.

Explanation:

For the reaction:

2NO(g) ⇌ N₂(g)+O₂(g),

Kc = [N₂][O₂] / [NO]².

At initial time: [NO] = 0.171 M, [N₂] = [O₂] = 0.0 M.

At equilibrium: [NO] = 0.171 M - 2x , [N₂] = [O₂] = x M.

∵ Kc = [N₂][O₂] / [NO]².

∴ 2400 = x² / (0.171 - 2x)² .

Taking the aquare root for both sides:

√(2400) = x / (0.171 - 2x)

48.99 = x / (0.171 - 2x)

48.99 (0.171 - 2x) = x

8.377 - 97.98 x = x

8.377 = 98.98 x.

∴ x = 8.464 x 10⁻².

∴ [NO] = 0.171 - 2(8.464 x 10⁻²) = 1.72 x 10⁻³ M.

∴ [N₂] = [O₂] = x = 8.464 x 10⁻² M.

3 0

2 years ago