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3 years ago

Please answer please please Physics

Physics

1 answer:

zmey [24]3 years ago

6 0

Answer:

about -1.26 m/s²

Explanation:

The acceleration can be found from the formula ...

a = (v2² -v1²)/(2d)

Here, we have the initial velocity v1=23 m/s, the final velocity v2=0, and teh distance d=210 m. Using the formula, we find the acceleration to be ...

a = (0 -23²)/2(210) ≈ -1.2595 . . . m/s²

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Answer:

Explanation:

Given

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mass of bus travelling in South direction is $m_2=1.578\times 10^4 kg$

speed of bus $v_2=12.2 km/h\approx 3.38\ m/s$

mass of each Passenger in south moving bus $m_0=64.8 kg$

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$P_1=m_1\times v_1$

$P_1=1.6\times 10^4\times 4.22$

$P_1=6.768\times 10^4 kg-m/s$

Momentum with south moving bus

$P_2=m_2\times v_2+n\cdot m_0\times v_2$

$P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38$

For total momentum to be towards south

$P_2-P_1$ should be greater than 0

thus for least value of n

$P_2=P_1$

$(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38=6.768\times 10^4$

$1.578\times 10^4+n\cdot 64.8=2.0023\times 10^4$

$n=\frac{4243.6686}{64.8}=65.48\approx 66$

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3 years ago

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If you jumped out of a plane, you would begin speeding up as you fall downward. Eventually, due to wind resistance, your velocit

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Answer:

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Answer:

W=315 x 10⁵ J

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F= 2.5 x 10⁵ N

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Lets take work done by catapult is W

W + F.d= K.E.

W= 5.4 x 10⁷ - 2.5 x 10⁵ x 90 J

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W=315 x 10⁵ J

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Explanation:

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3 years ago

Please answer please please Physics ​

Please answer please please Physics