What elements are in table salt
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Answer : Option (A) Accelerator 2 model has the lowest percentage of energy lost as waste.
Solution : Given,
For Accelerator 1 model,
Input energy = 2078.3 J
Wasted energy = 663.1 J
Output energy = 1415.2 J
For Accelerator 2 model,
Input energy = 7690.0 J
Wasted energy = 2337.5 J
Output energy = 5353.5 J
For Accelerator 3 model,
Input energy = 4061.9 J
Wasted energy = 2259.6 J
Output energy = 1802.3 J
Formula used for lowest percentage of energy lost as waste is:
% energy lost as waste = (Total energy wasted / Total input energy ) × 100
For Accelerator 1 model,
% energy lost as waste = = 31.90%
For Accelerator 2 model,
% energy lost as waste = = 30.39%
For Accelerator 3 model,
% energy lost as waste = = 55.62%
So, we conclude that the Accelerator 2 model has the lowest percentage of energy lost as waste.
Answer:- 1467 K
Solution:- It asks to calculate the kelvin temperature of the light bulb. Looking at the given info, it is based on ideal gas law equation, PV=nRT.
Given:
V = 75.0 mL = 0.0750 L
P = 116.8 kPa
We know that, 101.325 kPa = 1 atm
So,
= 1.15 atm
R is universal gas constant and it's value is .
T = ?
Let's plug in the values in the equation and solve it for T.
0.08625 = 0.00005878(T)
T = 1467 K
So, the temperature of the light bulb would be 1467 K.