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3 years ago

What elements are in table salt

Chemistry

1 answer:

Sedaia [141]3 years ago

4 0

The formula is NaCi, containing equal amounts of sodium and chloride

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1. Some athletes have as little as 3.0% body fat. If such a person has a body mass of 65 kg, how many pounds of body fat does th

77julia77 [94]

1. 3.0% ----> 3.0 kg fat= 100 kg body weigh
also remember that 1 kg= 2.20 lbs

$65 kg \frac{3.0 kg}{100 kg} x \frac{2.20 lb}{1 kg} = 4.29 lbs$

2. 0.94 g/mL----> 0.94 grams= 1 mL
1 Liters= 1000 mL
1kg= 1000 grams

$3 Liters \frac{1000 mL}{1 L} x \frac{0.94 grams}{1 mL} x \frac{1 kg}{1000 g} x \frac{2.20 lbs}{1 kg} = 6.20 lbs$

3 0

3 years ago

Read 2 more answers

When a hot piece of iron is placed in cool water,

Papessa [141]

A i believe is the answer

8 0

3 years ago

Ne4ueva [31]

Answer:

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

Explanation:

Volume of cylindrical reservoir = V

Radius of the cylindrical reservoir = r = d/2

d = diameter of the cylindrical reservoir = d = $4.50\times 10^1 m=45 m$

r = d/2 = 22.5 m

Depth of the reservoir = h = 10.0 m

$V=\pi r^2 h$

$=3.14\times (22.5 m)^2\times 10.0 m=15,896.25 m^3=15,896,250 L$

$1 m^3=1000 l$

Volume of water cylindrical reservoir : V

Density of water,d = 1 kg/L

Mass of water cylindrical reservoir = m

$m=d\times V=1 kg/L\times 15,896,250 L=15,896,250 kg$

1.6 kilogram of fluorine per million kilograms of water. (Given)

Concentration of fluorine in water = 1.6 kg/ 1000,000 kg of water

In 1000,000 kg of water = 1.6 kg of fluorine

Then $15,896,250 kg$ of water have x mass of fluorine:

$\frac{x}{15,896,250 kg\text{kg of water}}=\frac{1.6 kg}{1000,000 \text{kg of water}}$

$x=\frac{1.6 kg}{1000,000}\times 15,896,250 kg=25.434 kg$

15,896,250 kg water of contains mass 25.434 kg of fluorine.

25.434 kg = 25434 g

25,434 grams of fluorine should be added to give 1.6 ppm.

Percentage of fluorine in hydrogen hexafluorosilicate :

Molar mass hydrogen hexafluorosilicate = 144 g/mol

$F\%=\frac{6\times 19 g/mol}{144 g/mol}\times 100=79.16\%$

Total mass of hydrogen hexafluorosilicate = m'

$79.16\%=\frac{25,434 g}{m'}\times 100$

m' = 32,127.02 g

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

5 0

3 years ago

[Kr]5s^24d^105p^4

Margarita [4]

- Telleurium ( Te) is the chemical symbol
- electron is 52,
- there are 2 electron in 5s

7 0

4 years ago

Aspirin (C9H8O4) may be synthesized by mixing salicylic acid (C7H6O3) with excess acetic anhydride (C4H6O3).

diamong [38]

Answer:

65.18% is the percent yield for this reaction.

Explanation:

$C_7H_6O_3 + C_4H_6O_3\rightarrow C_9H_8O_4 + C_2H_4O_2$

Moles of salicyclic acid = $\frac{2.0 g}{138 g/mol}=0.01449 mol$

According to reaction 1 mole of salicyclic acid gives 1 mole of aspirin .

Then 0.01449 mole of salicylic acid will give :

$\frac{1}{1}\times 0.01449 mol=0.01449 mol$ of asprin

Mass of 0.01449 moles of aspirin :

= 0.01449 mol × 180 g/mol = 2.6082 g

Theoretical yield of aspirin = 2.6082 g

Experimental yield of aspirin = 1.7 g

The percent yield for this reaction:

$\%(Yield)=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$=\frac{1.7 g}{2.6082 g}\times 100=65.18\%$

65.18% is the percent yield for this reaction.

5 0

4 years ago