2 years ago

Describe a positive and negative net force acting on an object

1 answer:

8 0

There are different forces acting on an object like nuclear force , gravitational force...plus external forces like friction and other..

net sum of all these is resultnat

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One light-hour is the distance that light travels in an hour. How far is this, in kilometers? (Recall that the speed of light is

ycow [4]

Answer:

B 1.08 BILLION

Explanation:

SEE ATTACHMENT

Download pdf

6 0

2 years ago

A circuit breaker is rated for a current of 25 a rms at a voltage of 240 v rms. (a) what is the largest value of imax that the b

Mademuasel [1]

The largest value of current that the breaker can carry = Imax=35.4A

Explanation:

Rms value of current= Irms= 25 A

The rms current and the maximum current are related as

Imax= √2 Irms

Imax=√2 (25)

Imax=35.4 A

Thus the maximum current carried by the breaker= 35.4 A

8 0

3 years ago

Assuming no air resistance, how far will a 0.0010 kg raindrop have fallen when it hits the ground 30.0 s later. Assume g = 9.8 m

Serga [27]

D = (1/2)·at²
where d is the distance fallen, a is the acceleration (g in this problem), and t is the time
d = (1/2)·(9.8 m/s²)·(30 s)² = (1/2)·(9.8)·(900) m
d = 4410 m
The answer is b) 4410 m

Note: the mass of the raindrop is irrelevant since the acceleration due to gravity is independent of mass. (Galileo's Leaning Tower of Pisa experiment)

6 0

3 years ago

Read 2 more answers

When is the average velocity of an object equal to the instantaneous velocity?

atroni [7]

Answer:

Average velocity of an object is equal to the instantaneous velocity when it's acceleration is zero.

Explanation:

4 0

3 years ago

From the gravitational law calculate the weight W (gravitational force with respect to the earth) of a 89-kg man in a spacecraft

zhannawk [14.2K]

Answer:

$W=\frac{773}{4.45}=173.76 l b f$

Explanation:

$W=\frac{G \cdot m_{e} \cdot m}{(R+h)^{2}}$

The law of gravitation

$G=6.673\left(10^{-11}\right) m^{3} /\left(k g \cdot s^{2}\right)$

Universal gravitational constant [S.I. units]

$m_{e}=5.976\left(10^{24}\right) k g$

Mass of Earth [S.I. units]

$m=89 kg$

Mass of a man in a spacecraft [S.I. units]

$R=6371 \mathrm{~km}$

Earth radius [km]

Distance between man and the earth's surface

$h=261 \mathrm{~km} \quad[\mathrm{~km}]$

ESULT $W=\frac{6.673\left(10^{-11}\right) \cdot 5.976\left(10^{24}\right) \cdot 89}{\left(6371 \cdot 10^{3}+261 \cdot 10^{3}\right)^{2}}=773.22 \mathrm{~N}$

$W=\frac{773}{4.45}=173.76 l b f$

4 0

2 years ago