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AURORKA [14]
3 years ago
9

PLZ HELP ME!!!!!!!!

Physics
2 answers:
Nataly [62]3 years ago
8 0

<span>Each problem is worth 4 points.  Make sure you show your work!  </span>

<span>1.     </span>A note has a wavelength of 0.77955 m. If the speed of sound is 343.00 m/s, what pitch is this note?

f = (343m/s) / 0.77955m = 439.997 0r 440 Hz Pitch is an A.

 

<span>2.     </span>A note has a wavelength of 0.52028 m. If the speed of sound is 343.00 m/s, what pitch is this note?

f = (343 m/s) / 0.52028m = 659.26 Hz Pitch is an E

 

 

<span>3.     </span>A note has a wavelength of 0.65552 m. If the speed of sound is 343.00 m/s, what pitch is this note?

f= (343 m/s)/0.65552m = 523.25 Hz Pitch is a C

 

 

<span>4.     </span>A D note has a frequency of 587.33 Hz. Calculate its wavelength in meters.

λ= (343 m/s)/587.33Hz = 0.584 m

 

<span>5.     </span>A B note has a frequency of 493.88 Hz. Calculate its wavelength in meters.

<span>λ= (343 m/s)/493.88Hz=0.6945m</span>

mote1985 [20]3 years ago
4 0

Answer:

1.     Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.77955 m

now frequency is given by  

f = \frac{343m/s}{ 0.77955m}

f = 440 Hz  

2.     Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.52028 m

now frequency is given by  

f = \frac{343m/s}{ 0.52028m}

f = 659.3 Hz

3.     Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.65552 m

now frequency is given by  

f = \frac{343m/s}{ 0.65552m}

f = 523.25 Hz  

4.     Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 587.33 Hz

now wavelength is given by  

\lambda = \frac{343m/s}{587.33}

\lambda = 0.584 m    

5.     Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 493.88 Hz

now wavelength is given by  

\lambda = \frac{343m/s}{493.88}

\lambda = 0.6945 m    

6.     Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 698.46 Hz

now wavelength is given by  

\lambda = \frac{343m/s}{698.46}

\lambda = 0.491 m    

7.     Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.5840 m

now frequency is given by  

f = \frac{343m/s}{0.5840m}

f = 587.3 Hz  

8.     Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.4375 m

now frequency is given by  

f = \frac{343m/s}{0.4375m}

f = 784 Hz  

9.     Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 783.99 Hz

now wavelength is given by  

\lambda = \frac{343m/s}{783.99}

\lambda = 0.4375 m    

10.  Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 659.26 Hz

now wavelength is given by  

\lambda = \frac{343m/s}{659.26}

\lambda = 0.520 m    

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Following formulas will be used.

                                  x(t) = \frac{1}{2} t^2 = 12m =16.2m/s^2 t^2

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                                 V(t) = V_{o} +at

                                 x(t) = x_{0} +v_{0}t+\frac{1}{2}a t^2

(a) Calculating velocity right before going up the ramp.

 Wooden block is going on a straightaway and has net for on it.

         F_{n} =F-F_{s} = F-uF_{n}  = 100N-0.4*9.8m/s^2*5kg =81N

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      a = \frac{F}{m}=\frac{81}{5} =16.2m/s^2 .

With this acceleration, wooden block would reach at the foot of ramp in.

          x(t) = 12m = 16.2m/s^2*t^2

         t = 1.217s

and final velocity will be

v(t) = v_{0}+at = 0+16.2m/s^2*1.2171s = 19.7180m/s.

this velocity of wooden box just before going up the ramp.

(b) How far up the ramp will the wooden block go before stopping.

Ramp is at 20° relative to horizontal therefore velocity along the ramp that the wooden block would have will be.

                              V= V_{h}cos(20) = 18.5288m/s

and deceleration along the ramp is

                              a = \frac{F_{s} }{m}

 Where F_{s} force of friction along the inclined plane.

F_s =  uF_n = u*m*a

a = 9.8m/s^2*cos(20) = 9.2089m/s^2

is a component of g along normal of the inclined plane.

                               F_{s} = 0.25*5kg*9.2089m/s^2

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And with this deceleration time needed to get wooded block to stop is.

                     v(t) = v_o-at = 18.5288m/s-2.3022m/s^2*t = 0

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