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BaLLatris [955]
2 years ago
12

The base unit of length in the international system of units is the:

Physics
1 answer:
zavuch27 [327]2 years ago
5 0

The base unit of length in the international system of units is the: meter (m)

<h3>Meter</h3>

The meter, ( symbol: m ) is the SI unit of length. It is derived by taking the fixed numerical value of the speed of light in vacuum c to be 299 792 458 when expressed in the unit m s-1

<h3>International system of unit ( SI ) base units</h3>

The SI base units are the standard units of measurement defined which is defined by the International System of Units (SI) for the seven base quantities of what is now known as the International System of quantities:

Learn more about SI base units:

brainly.com/question/16393390

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Two charges are located in the x – y plane. If ????1=−4.10 nC and is located at (x=0.00 m,y=0.600 m) , and the second charge has
faust18 [17]

Answer:

The x-component of the electric field at the origin = -11.74 N/C.

The y-component of the electric field at the origin = 97.41 N/C.

Explanation:

<u>Given:</u>

  • Charge on first charged particle, q_1=-4.10\ nC=-4.10\times 10^{-9}\ C.
  • Charge on the second charged particle, q_2=3.80\ nC=3.80\times 10^{-9}\ C.
  • Position of the first charge = (x_1=0.00\ m,\ y_1=0.600\ m).
  • Position of the second charge = (x_2=1.50\ m,\ y_2=0.650\ m).

The electric field at a point due to a charge q at a point r distance away is given by

\vec E = \dfrac{kq}{|\vec r|^2}\ \hat r.

where,

  • k = Coulomb's constant, having value \rm 8.99\times 10^9\ Nm^2/C^2.
  • \vec r = position vector of the point where the electric field is to be found with respect to the position of the charge q.
  • \hat r = unit vector along \vec r.

The electric field at the origin due to first charge is given by

\vec E_1 = \dfrac{kq_1}{|\vec r_1|^2}\ \hat r_1.

\vec r_1 is the position vector of the origin with respect to the position of the first charge.

Assuming, \hat i,\ \hat j are the units vectors along x and y axes respectively.

\vec r_1=(0-x_1)\hat i+(0-y_1)\hat j\\=(0-0)\hat i+(0-0.6)\hat j\\=-0.6\hat j.\\\\|\vec r_1| = 0.6\ m.\\\hat r_1=\dfrac{\vec r_1}{|\vec r_1|}=\dfrac{0.6\ \hat j}{0.6}=-\hat j.

Using these values,

\vec E_1 = \dfrac{(8.99\times 10^9)\times (-4.10\times 10^{-9})}{(0.6)^2}\ (-\hat j)=1.025\times 10^2\ N/C\ \hat j.

The electric field at the origin due to the second charge is given by

\vec E_2 = \dfrac{kq_2}{|\vec r_2|^2}\ \hat r_2.

\vec r_2 is the position vector of the origin with respect to the position of the second charge.

\vec r_2=(0-x_2)\hat i+(0-y_2)\hat j\\=(0-1.50)\hat i+(0-0.650)\hat j\\=-1.5\hat i-0.65\hat j.\\\\|\vec r_2| = \sqrt{(-1.5)^2+(-0.65)^2}=1.635\ m.\\\hat r_2=\dfrac{\vec r_2}{|\vec r_2|}=\dfrac{-1.5\hat i-0.65\hat j}{1.634}=-0.918\ \hat i-0.398\hat j.

Using these values,

\vec E_2= \dfrac{(8.99\times 10^9)\times (3.80\times 10^{-9})}{(1.635)^2}(-0.918\ \hat i-0.398\hat j) =-11.74\ \hat i-5.09\ \hat j\  N/C.

The net electric field at the origin due to both the charges is given by

\vec E = \vec E_1+\vec E_2\\=(102.5\ \hat j)+(-11.74\ \hat i-5.09\ \hat j)\\=-11.74\ \hat i+(102.5-5.09)\hat j\\=(-11.74\ \hat i+97.41\ \hat j)\ N/C.

Thus,

x-component of the electric field at the origin = -11.74 N/C.

y-component of the electric field at the origin = 97.41 N/C.

4 0
3 years ago
A classroom that normally contains 40 people is to be airconditioned with window air-conditioning units of 5-kW cooling capacity
oksano4ka [1.4K]

Answer:

About  2 units.

Explanation:

We assume that there is no heat dissipating instrument in the room

Total cooling load of the room is defined from the given below equation

Q_{cooling}=Q_{light}+Q_{people}+Q_{heat gain}

where

Q_{light}= 10*100 W =1 KW

Q_{people} = 40*360 KJ/h= 4 KW

Q_{heat gain}=15000KJ/h= 4.17 KW

Q_{cooling}= 1+4+4.17=9.17 KW

the number of air conditioner unit is =\frac{9.17}{5}=1.83

 which is approximately 2 units

   

7 0
3 years ago
A window washer is standing on a scaffold supported by vertical ropes at each end. The scaffold weighs 200. N and is 3.00 m long
seropon [69]
<h2>Tension in ropes are 333.33 N and 566.67 N.</h2>

Explanation:

Refer the given figure showing the arrangement.

For having stability we have torque at A and B are zero.

        Sum of Torques at A = 0

        700 x 1 + 200 x 1.5 - Q x 3 = 0

                               3Q = 1000

                                  Q = 333.33 N

        Sum of Torques at B = 0

        200 x 1.5 + 700 x 2 - P x 3 = 0

                               3P = 1700

                                  P = 566.67 N  

Tension in ropes are 333.33 N and 566.67 N.

5 0
3 years ago
5. Analyze When you use a
Ad libitum [116K]

Answer: I don’t know Kiane I’m looking for the anwser too—Gianny

Explanation:

3 0
3 years ago
What happens to light at the surface of the water that creates the upside down image of the impalas?
mariarad [96]
B the light reflection
4 0
3 years ago
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