A 5-kg concrete block is lowered with a downward acceleration of 2.8 m/s2 by means of a rope. The force of the block on the Eart
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The bullet is moving by uniformly accelerated motion.
The initial velocity is
, the final velocity is 
, and the total time of the motion is 
, so the acceleration is given by
where the negative sign means that is a deceleration.
Therefore we can calculate the total distance covered by the bullet in its motion using
So, the bullet penetrates the sandbag 1.8 meters.
The bullet is moving by uniformly accelerated motion.
The initial velocity is
where the negative sign means that is a deceleration.
Therefore we can calculate the total distance covered by the bullet in its motion using
So, the bullet penetrates the sandbag 1.8 meters.
Answer:
Explanation:
As the path is straight, so the speed is equivalent to velocity. Now. assuming that the acceleration and deceleration of the train are constant. So, change of velocity with respect to time for acceleration as well as deceleration is constant. Hence, the slope of the speed-time graph is constant for the time of acceleration as well as deceleration. The speed for the time from to
is constant, so slope for this interval of time is zero. The speed-time graph is shown in the figure.
The total distance covered by the train during the entire journey is the area of the speed-time graph.
Area
As velocity is in and time is in
so the unit of area is
Hence, the total distance is .
