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Novay_Z [31]
3 years ago
15

Two forces that are not equal in size are

Physics
1 answer:
Bumek [7]3 years ago
4 0
They are unbalanced forces ..... Hope this helps :3
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An object that has a mass of 36.0kg is pushed along a horizontal surface with a force of 85.0N. IF
Oksana_A [137]

Answer:

0.36m/s^2

Explanation:

a=f/m

7 0
3 years ago
A tennis player serves a tennis ball such that it is moving horizontally when it leaves the racquet. When the ball travels a hor
finlep [7]

Answer:

The initial velocity is 38.46 m/s.

Explanation:

The horizontal distance travel by the tennis ball = 13 m  

The height at which the tennis ball dropped = 56 cm

Now calculate the initial speed of tennis ball.

The vertical velocity is zero.

Below is the calculation. Here, first convert centimetre into kilometre. So, height at which ball dropped is 0.56 km.

v = \sqrt{2 \times 9.8 \times 0.56} = 3.32 m/s \\

t = \frac{3.32}{9.8} = 0.338s \\

Ux \times t = 13 \\

Ux = \frac{13}{0.338} = 38.46 m/s = Initial velocity.

8 0
3 years ago
Mrs. Miller is acting a little strange and is pushing as hard as she can against a wall. Using Newton's Laws, what could be say
deff fn [24]
Newton’s 3rd Law of Motion
8 0
3 years ago
Read 2 more answers
If a car has a velocity of 85 km/hr, how long will it take to accelerate to 45 km/hr if the acceleration is -3 km/hr/sec?
weqwewe [10]

Answer:

Time, t = 13.34 seconds.

Explanation:

Given the following data;

Initial velocity, u = 85km/hr to meters per seconds = 85*1000/3600 = 23.61 m/s

Final velocity, v = 45km/hr to meters per seconds = 45*1000/3600 = 12.5 m/s

Acceleration, a = -3 km/hr/sec to meters per seconds square = -3*1000/3600 = -0.833m/s²

To find the time;

Acceleration = (v - u)/t

-0.833 = (12.5 - 23.61)/t

-0.833t = -11.11

t = 11.11/0.833

Time, t = 13.34 seconds.

6 0
3 years ago
Suppose you're performing experiments in science class in which you start with 70 bacteria and the amount of bacteria triples ev
barxatty [35]
1h----------------> 70x3=210 bacteria
2h-----------------> 210*3=630 bactaeria
let be y the number of bacteria at the t=0h
it is y=70 3^0
for t= 1h
y=70*3^1=210
for t=2h
y=70*3^2=630

so we can write y=70*3^x, where x is the number of hour


5 0
4 years ago
Read 2 more answers
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