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3 years ago

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Need help on number 5 and 6

2 answers:

Hitman42 [59]3 years ago

5 0

Answer:

b and c

Explanation:

hopes this helps i took the test.

Whitepunk [10]3 years ago

4 0

Answer:

jowieahudsfnkdmlew2l,poeq3riugjnkfmdko

Explanation:

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A satellite is in a circular orbit around the Earth at an altitude of 2.80 3 106 m. Find (a) the period of the orbit, (b) the sp

Katen [24]

Explanation:

Given that,

Altitude $h= 2.803\times10^{6}\ m$

We need to calculate the radius

$r=R+h$

Where, R = radius of the earth

h = radius of altitude

Put the value into the formula

$r=(6.38\times10^{6}+2.803\times10^{6})$

$r=9.18\times10^{6}\ m$

(a). We need to calculate the period of the orbit,

Using formula of period

$T^2=\dfrac{4\pi^2}{GM}r^3$

$T^2=\dfrac{4\pi^2}{6.67\times10^{-11}\times5.98\times10^{24}}\times(9.18\times10^{6})^3$

$T^2=76570372.9509\ sec$

$T=8750.45\ sec$

(b). We need to calculate the speed of the satellite

Using formula of speed

$v^2=\dfrac{GM}{r}$

Put the value into the formula

$v^2=\dfrac{6.67\times10^{-11}\times5.98\times10^{24}}{9.18\times10^{6}}$

$v^2=43449455.3377\ m/s$

$v=6.59\times10^{3}\ m/s$

(c). We need to calculate the acceleration of the satellite

Using formula of acceleration

$a_{c}=\dfrac{v^2}{r}$

Put the value into the formula

$a_{c}=\dfrac{(6.59\times10^{3})^2}{9.18\times10^{6}}$

$a_{c}=4.73\ m/s^2$

Hence, This is the required solution.

6 0

4 years ago

A small wooden block with mass 0.750 kg is suspended from the lower end of a light cord that is 1.72 m long. The block is initia

Ierofanga [76]

Answer:

$v_{0}=319.2 m/s$

Explanation:

We need to use the momentum and energy conservation.

$p_{0}}=p_{f}$

$mv_{0}=(m+M)V_{1}$

Where:

m is the mass of bullet (m=0.01 kg)
M is the mass of the wooden (M=0.75 kg)
v(0) initial velocity of bullet
V(1) is the velocity of the combined object in the moment the bullet hist the block

Conservation of energy.

We have kinetic energy at first and kinetic and potential energy at the end.

$(1/2)(m+M)V_{1}^{2}=(1/2)(m+M)V_{2}^{2}+(m+M)gh$

Here:

V(1) is the velocity of the combined at the initial position
h is the vertical height ( h = 0.800 m)

We can find V(2) using the definition of force at this point:

$\Sigma F=(m+M)a_{c}=(m+M)(V_{2}^{2}/R)$

$T-(m+M)gcos(\theta)=(m+M)a_{c}=(m+M)(V_{2}^{2}/R)$

$cos(\theta) =(L-h)/L=(1.72-0.8)/1.72$

$\theta =57.66$

Now, we can solve the equation to find V(2)

$V_{2}=\sqrt{\frac{R*(T-(m+M)*g*cos(\theta))}{(m+M)}}$

$V_{2}=\sqrt{\frac{1.72*(4.86-(0.01+0.75)*9.81*cos(57.66))}{(0.01+0.75)}}$

$V_{2}=1.40 m/s$

Now we can find V(1) using the conservation of energy equation

$(1/2)V_{1}^{2}=(1/2)V_{2}^{2}+gh$

$V_{1}=\sqrt{V_{2}^{2}+2gh}$

$V_{1}=\sqrt{1.40^{2}+2*9.81*0.8}$

$V_{1}=4.20 m/s$

Finally, using the momentum equation we find v(0)

$v_{0}=\frac{(m+M)V_{1}}{m}$

$v_{0}=\frac{(0.01+0.75)*4.20}{0.01}$

$v_{0}=319.2 m/s$

I hope it helps you!

7 0

4 years ago

What is the scientific definition of energy that relates to work

Luba_88 [7]

Work can be defined as change in kinetic energy

4 0

3 years ago

Read 2 more answers

A 120 V electric heater draws a current of 14.1 A. What is the resistance, in ohms?

Sav [38]

Answer:

8.5 ohms

Explanation:

from ohms law

V=IR

120=14.1R

divide both sides by 14.1

120/14.1=14.1R/14.1

R=8.5ohms

5 0

3 years ago

Read 2 more answers

Matter can exist in hw many states

Mariulka [41]

Answer:

Matter can exist in four different states: solids, liquids, gases and plasma.

Explanation:

Hope this helps :)

4 0

3 years ago