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Roman55 [17]
3 years ago
11

Flower bed is filled with five types of flowers. Which placement of the flowers represents the highest entropy?

Physics
2 answers:
inessss [21]3 years ago
4 0

ANSEWER :B IN ROWS ONLY

mars1129 [50]3 years ago
3 0

Answer:

B

Explanation:

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Llana [10]

Answer:

we cant see the digram bro

Explanation:

6 0
3 years ago
A 66.0 kg diver is 3.10 m above the water, falling at speed of 6.10 m/s. Calculate her kinetic energy as she hits the water. (Ne
castortr0y [4]

Kinetic energy as she hits the water is 3300 joule.

To find the answer, we need to know about the Newton's equation of motion.

<h3>What's the Newton's equation of motion to determine the final velocity?</h3>
  • The final velocity is determined as

V²=U²+2aS

  • V= final velocity, U= initial velocity, a= acceleration and S= distance
<h3>What's the final velocity of the driver falling from 3.10m with initial velocity of 6.10m/s?</h3>
  • Here, a= 9.8m/s², U= 6.10m/s and S= 3.10m
  • So, V²= 6.1²+2×9.8×3.10= 98
  • V= √98= 10m/s
<h3>What's the kinetic energy of the driver when touches the water?</h3>

Kinetic energy= 1/2×mass×velocity²

= 1/2 × 66 × 10²

= 3300J

Thus, we can conclude that the kinetic energy of the driver is 3300 Joule.

Learn more about the kinetic energy here:

brainly.com/question/25959744

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3 0
2 years ago
ANSWER THIS FOR BRAINY CROWN B) ITS SO EASY!
Luda [366]

Answer:

300

Explanation:

3 0
3 years ago
Read 2 more answers
Work out the kinetic energy of a 2.5 kg remote-controlled car that is moving at 2 m/s.
lbvjy [14]

Answer: 5 joules

Explanation:

mass=m=2.5kg

Velocity=v=2m/s

Kinetic energy=ke

ke=(m x v x v)/2

ke=(2.5 x 2 x 2)/2

Ke=10/2

Ke=5

Kinetic energy=5 joules

8 0
3 years ago
A diffraction pattern is formed on a screen 130 cm away from a 0.420-mm-wide slit. Monochromatic 546.1-nm light is used. Calcula
notka56 [123]

Answer:

The fractional Intensity \frac{I}{I_{max}} = 0.0146

Given:

wavelength of the light, \lambda = 546.1 nm = 546.1\times 10^{-9} m

slit and screen separation difference, D = 130 cm = 1.3 m

distance of the point from the center of the principal maximum, y = 4.10 mm = 0.041 m

slit width, d = 0.420 mm = 0.420\times 10^{-3}

Solution:

To calculate the fractional intensity, we use the given formula:

\frac{I}{I_{max}} = \frac{sin^{2}\delta }{\frac({\delta}{2})^{2}}             (1)

\delta = \frac{\pi }{\lambda}dsin\theta    

For very small angle:                                        

\delta = \frac{\pi dy}{\lambda D}                                  (2)

where

\delta = total phase angle

\theta = angle of deviation

Using eqn (2):

\delta = \frac{\pi \times 0.42\times 10^{-3}\times 4.1\times 10^{-3} }{546.1\times 10^{-9}\times 1.3} = 7.6202 radians

Now, using eqn (1):

\frac{I}{I_{max}} = \frac{sin^{2}(7.6202) }{(\frac{7.6202}{2})^{2}} = 0.0146

4 0
4 years ago
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