The radius of a cone with a curved surface area of 140π cm² and a slant height of 5 cm will be 28 cm.
<h3>What is curved surface area?</h3>
The region with just curved surfaces, leaving the circular top and base, is referred to as the curved surface area. Total Surface Area is the combined area of the bases and the curved surface. The measurement of a solid's curved surface area is its outer area, which excludes the top and bottom extensions. Surface area of the cylinder that is curved: A right circular cylinder is the solid that results when a rectangle circles around one side and makes a full revolution. The curved surface area of a cylinder (CSA) is also known as the lateral surface area and is defined as the area of the curved surface of any given cylinder having a base radius "r" and height "h".
Here,
Curved surface area of cone=πrl
=140π
l=5 cm
140π=πr*5
r=140/5
r=28 cm
The radius of cone that has 5 cm as slant height and 140π cm² as the curved surface area will be 28 cm.
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Answer: According with the graph, the input value for which the statement f(x)=g(x) is true (the value of "x" where the graph intersect) is 1.5 (third option).
Solution
The input value for which the statement f(x) = g(x) is true, is the value of "x" where the graph of the two functions intersect. Accordind with the graph, the two functions f(x) and g(x) intersect at x between 1 and 2, approximately at x=1.5
Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
The answer is C 200
Because 10 / 200 = 0.05 * 100 = 5%
I hope this helps :)
f(x)=x3−5
Replace f(x)
with y
.
y=x3−5
Interchange the variables.
x=y3−5
Solve for y
.
Since y
is on the right side of the equation, switch the sides so it is on the left side of the equation.
y3−5=x
Add 5
to both sides of the equation.
y3=5+x
Take the cube root of both sides of the equation to eliminate the exponent on the left side.
y=3√5+x
Solve for y
and replace with f−1(x)
.
Replace the y
with f−1(x)
to show the final answer.
f−1(x)=3√5+x
Set up the composite result function.
f(g(x))
Evaluate f(g(x))
by substituting in the value of g into f
.
(3√5+x)3−5
Simplify each term.
Remove parentheses around 3√5+x
.
f(3√5+x)=3√5+x3−5
Rewrite 3√5+x3
as 5+x
.
f(3√5+x)=5+x−5
Simplify by subtracting numbers.
.
Subtract 5
from 5
.
f(3√5+x)=x+0
Add x
and 0
.
f(3√5+x)=x
Since f(g(x))=x
, f−1(x)=3√5+x is the inverse of f(x)=x3−5
.
f−1(x)=3√5+x
